1
JEE Advanced 2019 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
A conducting wire of parabolic shape, initially y = x2, is moving with velocity $$v = {v_0}\widehat i$$ in a non-uniform magnetic field $$B = {B_0}\left( {1 + {{\left( {{y \over L}} \right)}^\beta }} \right)\widehat k$$, as shown in figure. If V0, B0, L and $$\beta $$ are positive constants and $$\Delta $$$$\phi $$ is the potential difference developed between the ends of the wire, then the correct statement(s) is/are

JEE Advanced 2019 Paper 1 Offline Physics - Electromagnetic Induction Question 14 English
A
$$\left| {\Delta \phi } \right| = {4 \over 3}{B_0}{V_0}L$$ for $$\beta $$ = 2
B
$$\left| {\Delta \phi } \right|$$ remains the same if the parabolic wire is replaced by a straight wire, y =x initially, of length $$\sqrt 2 L$$
C
$$\left| {\Delta \phi } \right|$$ = $${1 \over 2}{B_0}{V_0}L$$ for $$\beta $$ = 0
D
$$\left| {\Delta \phi } \right|$$ is proportional to the length of the wire projected on the y-axis.
2
JEE Advanced 2018 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
In the figure below, the switches $${S_1}$$ and $${S_2}$$ are closed simultaneously at $$t=0$$ and a current starts to flow in the circuit. Both the batteries have the same magnitude of the electromotive force (emf) and the polarities are as indicated in the figure. Ignore mutual inductance between the inductors. The current $$I$$ in the middle wire reaches its maximum magnitude $${I_{\max }}$$ at time $$t = \tau $$ . Which of the following statements is (are) true?

JEE Advanced 2018 Paper 1 Offline Physics - Electromagnetic Induction Question 16 English
A
$${I_{\max }} = {V \over {2R}}$$
B
$${I_{max}} = {V \over {4R}}$$
C
$$\tau = {L \over R}\ln 2$$
D
$$\tau = {{2L} \over R}\ln 2$$
3
JEE Advanced 2017 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2
Change Language
A source of constant voltage V is connected to a resistance R and two ideal inductors L1 and L2 through a switch S as shown. There is no mutual inductance between the two inductors. The switch S is initially open. At t = 0, the switch is closed and current begins to flow. Which of the following options is/are correct?

JEE Advanced 2017 Paper 2 Offline Physics - Electromagnetic Induction Question 8 English
A
After a long time, the current through L1 will be $${V \over R}{{{L_2}} \over {{L_1} + {L_2}}}$$
B
After a long time, the current through L2 will be $${V \over R}{{{L_1}} \over {{L_1} + {L_2}}}$$
C
The ratio of the currents through L1 and L2 is fixed at all times (t > 0)
D
At t = 0, the current through the resistance R is $${V \over R}$$
4
JEE Advanced 2017 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
A circular insulated copper wire loop is twisted to form two loops of area $$A$$ and $$2A$$ as shown in the figure. At the point of crossing the wires remain electrically insulated from each other. The entire loop lies in the plane (of the paper). A uniform magnetic field $$\overrightarrow B $$ points into the plane of the paper. At $$t=0,$$ the loop starts rotating about the common diameter as axis with a constant angular velocity $$\omega $$ in the magnetic field.

Which of the following options is/are correct?

JEE Advanced 2017 Paper 1 Offline Physics - Electromagnetic Induction Question 15 English
A
The emf induced in the loop is proportional to the sum of the areas of the two loops
B
The amplitude of the maximum net emf induced due to both the loops is equal to the amplitude if maximum emf induced in the smaller loop alone
C
The net emf induced due to both the loops is proportional to $$\cos \,\omega t$$
D
The rate of change of the flux is maximum when the plane of the loops is perpendicular to plane of the paper
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