1
JEE Advanced 2019 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
Molar conductivity ($$\Lambda $$m) of aqueous solution of sodium stearate, which behaves as a strong electrolyte, is recorded at varying concentrations (C) of sodium stearate. Which one of the following plots provides the correct representation of micelle formation in the solution?

(critical micelle concentration (CMC) is marked with an arrow in the figures)
A
JEE Advanced 2019 Paper 1 Offline Chemistry - Electrochemistry Question 10 English Option 1
B
JEE Advanced 2019 Paper 1 Offline Chemistry - Electrochemistry Question 10 English Option 2
C
JEE Advanced 2019 Paper 1 Offline Chemistry - Electrochemistry Question 10 English Option 3
D
JEE Advanced 2019 Paper 1 Offline Chemistry - Electrochemistry Question 10 English Option 4
2
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
For the following cell,

$$Zn\left( s \right)\left| {ZnS{O_4}\left( {aq} \right)} \right|\left| {CuS{O_4}\left( {aq} \right)} \right|Cu\left( s \right)$$

when the concentration of $$Z{n^{2 + }}$$ is $$10$$ times the concentration of $$C{u^{2 + }},$$ the expression for $$\Delta G$$ (in $$J\,mo{l^{ - 1}}$$) is [$$F$$ is Faraday constant; $$R$$ is gas constant; $$T$$ is temperature; $${E^0}$$ (cell)$$=1.1$$ $$V$$]
A
$$1.1F$$
B
$$2.303RT-2.2F$$
C
$$2.303RT+1.1F$$
D
$$-2.2F$$
3
JEE Advanced 2016 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
For the following electrochemical cell at 298 K
Pt(s) | H2 (g, 1 bar) | H+ (aq, 1 M) || M4+ (aq), M2+ (aq) | Pt (s)
Ecell = 0.092 V when $${{\left[ {{M^{2 + }}(aq)} \right]} \over {\left[ {{M^{4 + }}(aq)} \right]}}$$ = 10x
Give, $$E_{{M^{4 - }}/{M^{2 + }}}^o$$ = 0.151 V; 2.303 RT/F = 0.059 V

The value of x is

A
-2
B
-1
C
1
D
2
4
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+6
-1.5
The standard reduction potential data at 25oC is given below:
Eo (Fe3+ , Fe2+) = +0.77V;
Eo (Fe2+ , Fe) = -0.44V;
Eo (Cu2+ , Cu) = +0.34V;
Eo (Cu+ , Cu) = +0.52V;
Eo [O2(g) + 4H+ + 4e- $$\to$$ 2H2O] = +1.23V;
Eo [O2(g) + 2H2O + 4e- $$\to$$ 4OH-] = +0.40 V
Eo (Cr3+ , Cr) = -0.74V;
Eo (Cr2+ , Cr) = -0.91V;

Match Eo of the redox pair in List – I with the values given in List – II and select the correct answer using the code given below the lists:

List - I
P. Eo (Fe3+ , Fe)
Q. Eo (4H2O $$\leftrightharpoons$$ 4H+ + 4OH-)
R. Eo (Cu2+ + Cu $$\to$$ 2Cu+)
S. Eo (Cr3+, Cr2+)

List - II
1. -0.18 V
2. -0.4 V
3. -0.04 V
4. -0.83 V
A
P - 4; Q - 1; R - 2; S - 3
B
P - 2; Q - 3; R - 4; S - 1
C
P - 1; Q - 2; R - 3; S - 4
D
P - 3; Q - 4; R - 1; S - 2
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