1
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Change Language
For the following cell,

$$Zn\left( s \right)\left| {ZnS{O_4}\left( {aq} \right)} \right|\left| {CuS{O_4}\left( {aq} \right)} \right|Cu\left( s \right)$$

when the concentration of $$Z{n^{2 + }}$$ is $$10$$ times the concentration of $$C{u^{2 + }},$$ the expression for $$\Delta G$$ (in $$J\,mo{l^{ - 1}}$$) is [$$F$$ is Faraday constant; $$R$$ is gas constant; $$T$$ is temperature; $${E^0}$$ (cell)$$=1.1$$ $$V$$]
A
$$1.1F$$
B
$$2.303RT-2.2F$$
C
$$2.303RT+1.1F$$
D
$$-2.2F$$
2
JEE Advanced 2016 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
For the following electrochemical cell at 298 K

Pt(s) | H2 (g, 1 bar) | H+ (aq, 1 M) || M4+ (aq), M2+ (aq) | Pt (s)

Ecell = 0.092 V when $${{\left[ {{M^{2 + }}(aq)} \right]} \over {\left[ {{M^{4 + }}(aq)} \right]}}$$ = 10x

Give, $$E_{{M^{4+}}/{M^{2 + }}}^o$$ = 0.151 V; 2.303 RT/F = 0.059 V

The value of x is

A
-2
B
-1
C
1
D
2
3
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+6
-1.5
An aqueous solution of X is added slowly to an aqueous solution of Y as shown in List – I. The variation in conductivity of these reactions in List – II. Match List – I with List – II and select the correct answer using the code given below the lists:

List - I
P. $$\mathop {(C{}_2{H_5}){}_3N}\limits_X $$ + $$\mathop {C{H_3}COOH}\limits_Y $$
Q. $$\mathop {KI(0.1M)}\limits_X $$ + $$\mathop {AgN{O_3}(0.01M)}\limits_Y $$
R. $$\mathop {C{H_3}COOH}\limits_X $$ + $$\mathop {KOH}\limits_Y $$
S. $$\mathop {NaOH}\limits_X $$ + $$\mathop {HI}\limits_Y $$

List - II
1. Conductivity decreases then increases
2. Conductivity decreases then does not change much
3. Conductivity increases then does not change much
4. Conductivity does not change much then increases
A
P - 3; Q - 4; R - 2; S - 1
B
P - 4; Q - 3; R - 2; S - 1
C
P - 2; Q - 3; R - 4; S - 1
D
P - 1; Q - 4; R - 3; S - 2
4
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+6
-1.5
The standard reduction potential data at 25oC is given below:
Eo (Fe3+ , Fe2+) = +0.77V;
Eo (Fe2+ , Fe) = -0.44V;
Eo (Cu2+ , Cu) = +0.34V;
Eo (Cu+ , Cu) = +0.52V;
Eo [O2(g) + 4H+ + 4e- $$\to$$ 2H2O] = +1.23V;
Eo [O2(g) + 2H2O + 4e- $$\to$$ 4OH-] = +0.40 V
Eo (Cr3+ , Cr) = -0.74V;
Eo (Cr2+ , Cr) = -0.91V;

Match Eo of the redox pair in List – I with the values given in List – II and select the correct answer using the code given below the lists:

List - I
P. Eo (Fe3+ , Fe)
Q. Eo (4H2O $$\leftrightharpoons$$ 4H+ + 4OH-)
R. Eo (Cu2+ + Cu $$\to$$ 2Cu+)
S. Eo (Cr3+, Cr2+)

List - II
1. -0.18 V
2. -0.4 V
3. -0.04 V
4. -0.83 V
A
P - 4; Q - 1; R - 2; S - 3
B
P - 2; Q - 3; R - 4; S - 1
C
P - 1; Q - 2; R - 3; S - 4
D
P - 3; Q - 4; R - 1; S - 2
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