1
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A body of mass m is taken from earth surface to a height h equal to twice the radius of earth, the increase in potential energy will be ($g$ = acceleration due to gravity on earth's surface) (R - radius of earth)
A
$\dfrac{2}{3}\text{mgR}$
B
$\dfrac{1}{3}\text{mgR}$
C
$\dfrac{1}{2}\text{mgR}$
D
$3\text{mgR}$
2
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
The time taken by simple pendulum for one oscillation is T on earth's surface. Its time period becomes xT when taken to a height R (equal to earth's radius) above the earth's surface. The value of x is
A
$\dfrac{1}{4}$
B
$\dfrac{1}{2}$
C
$2$
D
$4$
3
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
The masses and radii of the earth and moon are $M_1$, $R_1$ and $M_2$, $R_2$ and respectively, Their centres are at a distance 'd' apart. The minimum speed with which body of mass 'm' should be projected from a distance $2d/3$ from the centre of $M_1$ so as to escape to infinity is
A
$\sqrt{\dfrac{6G}{d}(2M_1 + M_2)}$
B
$\sqrt{\dfrac{6G}{d}(M_1 - 2M_2)}$
C
$\sqrt{\dfrac{3G}{d}(M_1 + 2M_2)}$
D
$\sqrt{\dfrac{8G}{d}(M_1 - 2M_2)}$
4
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
The distance of the two planets A and B from the sun are '$r_A$' and '$r_B$' respectively such that $r_B = 100\, r_A$. The ratio of the speed of planet A to that of planet B is (both the planets are revolving around the sun)
A
$\dfrac{1}{\sqrt{10}}$
B
$\sqrt{10}$
C
$10$
D
$10\sqrt{10}$

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