MHT CET 2025 23rd April Morning Shift | Gravitation Question 4 | Physics

A uniform solid sphere of mass ' $m$ ' and radius ' r ' is surrounded by a uniform thin spherical shell of radius ' $2 r$ ' and mass ' $m$ ' then the gravitational field

at a distance of 15 r from the centre is

$$ \frac{2}{9} \frac{\mathrm{Gm}}{\mathrm{r}^2} $$

at a distance of (2.5)r from the centre is

$$ \frac{8}{25} \frac{\mathrm{Gm}}{\mathrm{r}^2} $$

at a distance of (1.5)r from the centre is zero.

between the sphere and spherical shell is uniform.

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

-0

The magnitude of gravitational potential energy of a body at a distance ' $R$ ' from the centre of the earth is ' E '. Its weight at a distance ' 1.5 R ' from the centre of the earth is

$\frac{2 \mathrm{E}}{9 \mathrm{R}}$

$\frac{4 E}{5 R}$

$\frac{4 E}{9 R}$

$\frac{2 E}{7 R}$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

Time period of a simple pendulum on earth's surface is ' T '. It time period becomes ' xT ' when taken to a height ' $2 R$ ' above earth's surface. The value of $x$ will be $(R=$ radius of earth)

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

Two satellites P and Q go round a planet in circular orbits having radii ' $3 R$ ' and ' $R$ ' respectively. If the speed of satellite $P$ is ' $2 V$ ', the speed of the satellite $Q$ will be

$2 \sqrt{3} \mathrm{~V}$

$\frac{2 \mathrm{~V}}{\sqrt{3}}$

$\frac{\mathrm{V}}{2}$

$\frac{\mathrm{V}}{\sqrt{3}}$

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