MHT CET 2021 21th September Morning Shift | Gravitation Question 78 | Physics

A pendulum is oscillating with frequency '$$n$$' on the surface of the earth. It is taken to a depth $$\frac{R}{2}$$ below the surface of earth. New frequency of oscillation at depth $$\frac{R}{2}$$ is

[ $$R$$ is the radius of earth]

$$\mathrm{\frac{n}{3}}$$

$$\frac{\mathrm{n}}{\sqrt{2}}$$

$$\mathrm{2 n}$$

$$\frac{\mathrm{n}}{2}$$

MHT CET 2021 21th September Morning Shift

MCQ (Single Correct Answer)

-0

When the value of acceleration due to gravity '$$g$$' becomes $$\frac{g}{3}$$ above surface of height '$$h$$' then relation between '$$h$$' and '$$R$$' is ( $$\mathrm{R}=$$ radius of earth)

$$\mathrm{h}=\frac{\mathrm{R}}{\sqrt{3}-1}$$

$$\mathrm{h}=\frac{\sqrt{3}}{\mathrm{R}}$$

$$h=(\sqrt{2}-1) R$$

$$\mathrm{h}=(\sqrt{3}-1) \mathrm{R}$$

MHT CET 2021 21th September Morning Shift

MCQ (Single Correct Answer)

-0

A particle of mass '$$m$$' is kept at rest at a height $$3 R$$ from the surface of earth, where '$$R$$' is radius of earth and '$$M$$' is the mass of earth. The minimum speed with which it should be projected, so that it does not return back is ( $$g=$$ acceleration due to gravity on the earth's surface)

$$\left[\frac{\mathrm{GM}}{2 \mathrm{R}}\right]^{1 / 2}$$

$$\left[\frac{\mathrm{gR}}{4}\right]^{1 / 2}$$

$$\left[\frac{2 \mathrm{~g}}{\mathrm{R}}\right]^{1 / 2}$$

$$\left[\frac{\mathrm{GM}}{\mathrm{R}}\right]^{1 / 2}$$

MHT CET 2021 20th September Evening Shift

MCQ (Single Correct Answer)

-0

A body is projected from earth's surface with thrice the escape velocity from the surface of the earth. What will be its velocity when it will escape the gravitational pull?

$$2 \mathrm{~V}_{\mathrm{e}}$$

$$4 \mathrm{~V}_{\mathrm{e}}$$

$$2 \sqrt{2} \mathrm{~V}_{\mathrm{e}}$$

$$\frac{\mathrm{V}_{\mathrm{e}}}{2}$$

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