1
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A boy weighs 72 N on the surface of earth. The gravitational force on a body due to earth at a height equal to half the radius of earth will be

A
32 N
B
48 N
C
96 N
D
162 N
2
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A satellite is orbiting just above the surface of the planet of density ' $\rho$ ' with periodic time ' $T$ '. The quantity $\mathrm{T}^2 \rho$ is equal to ( $\mathrm{G}=$ universal gravitational constant)

A
$\frac{4 \pi^2}{G}$
B
$\frac{3 \pi^2}{G}$
C
$\frac{3 \pi}{G}$
D
$\frac{\pi}{G}$
3
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The speed with which the earth would have to rotate about its axis so that a person on the equator would weigh $\frac{3}{5}$ th as much as at present weight is ( $\mathrm{g}=$ gravitational acceleration, $\mathrm{R}=$ equatorial radius of the earth)

A
$\sqrt{\frac{2 g}{5 R}}$
B
$\sqrt{\frac{3 \mathrm{~g}}{5 \mathrm{R}}}$
C
$\sqrt{\frac{5 R}{3 g}}$
D
$\sqrt{\frac{3}{5}} \mathrm{gR}$
4
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum has a periodic time ' $\mathrm{T}_1$ ' when it is on the surface of earth of radius ' $R$ '. Its periodic time is ' $\mathrm{T}_2$ ' when it is taken to a height ' $R$ ' above the earth's surface. The value of $\frac{T_2}{T_1}$ is

A
$\sqrt2$
B
1
C
2
D
$\frac{1}{2}$
MHT CET Subjects
EXAM MAP