1
MHT CET 2021 20th September Morning Shift
+1
-0

The depth 'd' below the surface of the earth where the value of acceleration due to gravity becomes $$\left(\frac{1}{n}\right)$$ times the value at the surface of the earth is $$(R=$$ radius of the earth)

A
$$\mathrm{R}\left(\frac{\mathrm{n}-1}{\mathrm{n}}\right)$$
B
$$R\left(\frac{n}{n+1}\right)$$
C
$$\frac{R}{n}$$
D
$$\frac{\mathrm{R}}{\mathrm{n}^2}$$
2
MHT CET 2021 20th September Morning Shift
+1
-0

The orbital velocity of an artificial satellite in a circular orbit just above the earth's surface is 'V'. For the satellite orbiting at an altitude of half the earth's radius, the orbital velocity is

A
$$\frac{3}{2}$$V
B
$$\sqrt{\frac{3}{2}}$$V
C
$$\sqrt{\frac{2}{3}}$$V
D
$$\frac{2}{3}$$V
3
MHT CET 2020 16th October Morning Shift
+1
-0

The mass of earth is 81 times the mass of the moon and the distance between their centres is $$R$$. The distance from the centre of the earth, where gravitational force will be zero is

A
$$\frac{R}{4}$$
B
$$\frac{R}{2}$$
C
$$\frac{9 R}{10}$$
D
$$\frac{R}{81}$$
4
MHT CET 2020 16th October Morning Shift
+1
-0

A body is thrown from the surface of the earth velocity $$\mathrm{v} / \mathrm{s}$$. The maximum height above the earth's surface upto which it will reach is ($$R=$$ radius of earth, $$g=$$ acceleration due to gravity)

A
$$\frac{v R}{2 g R-v}$$
B
$$\frac{2 g A}{v^2(R-1)}$$
C
$$\frac{v R^2}{g R-v}$$
D
$$\frac{v^2 R}{2 g R-v^2}$$
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