MHT CET 2025 23rd April Evening Shift | Gravitation Question 3 | Physics

The gravitational pull of the moon is $\left(\frac{1}{6}\right)^{th}$ of the earth and mass of moon is $\left(\frac{1}{8}\right)^{\text {th }}$ of the earth. This implies that the

radius of moon is $(1 / 4)^{\text {th }}$ of the earth's radius.

radius of the earth is $(\sqrt{4 / 3})^{\text {th }}$ of the moon's radius.

moon's radius is half that of the earth.

radius of the earth is $(4 / 3)^{\text {th }}$ of the moon's radius.

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

-0

A uniform solid sphere of mass ' $m$ ' and radius ' r ' is surrounded by a uniform thin spherical shell of radius ' $2 r$ ' and mass ' $m$ ' then the gravitational field

at a distance of 15 r from the centre is

$$ \frac{2}{9} \frac{\mathrm{Gm}}{\mathrm{r}^2} $$

at a distance of (2.5)r from the centre is

$$ \frac{8}{25} \frac{\mathrm{Gm}}{\mathrm{r}^2} $$

at a distance of (1.5)r from the centre is zero.

between the sphere and spherical shell is uniform.

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

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The magnitude of gravitational potential energy of a body at a distance ' $R$ ' from the centre of the earth is ' E '. Its weight at a distance ' 1.5 R ' from the centre of the earth is

$\frac{2 \mathrm{E}}{9 \mathrm{R}}$

$\frac{4 E}{5 R}$

$\frac{4 E}{9 R}$

$\frac{2 E}{7 R}$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

Time period of a simple pendulum on earth's surface is ' T '. It time period becomes ' xT ' when taken to a height ' $2 R$ ' above earth's surface. The value of $x$ will be $(R=$ radius of earth)

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