MHT CET 2020 16th October Morning Shift | Gravitation Question 89 | Physics

The mass of earth is 81 times the mass of the moon and the distance between their centres is $$R$$. The distance from the centre of the earth, where gravitational force will be zero is

$$\frac{R}{4}$$

$$\frac{R}{2}$$

$$\frac{9 R}{10}$$

$$\frac{R}{81}$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

A body is thrown from the surface of the earth velocity $$\mathrm{v} / \mathrm{s}$$. The maximum height above the earth's surface upto which it will reach is ($$R=$$ radius of earth, $$g=$$ acceleration due to gravity)

$$\frac{v R}{2 g R-v}$$

$$\frac{2 g A}{v^2(R-1)}$$

$$\frac{v R^2}{g R-v}$$

$$\frac{v^2 R}{2 g R-v^2}$$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

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Consider a particle of mass $m$ suspended by a string at the equator. Let $R$ and $M$ denote radius and mass of the earth. If $\omega$ is the angular velocity of rotation of the earth about its own axis, then the tension on the string will be $\left(\cos 0^{\circ}=1\right)$

$\frac{G M m}{R^2}$

$\frac{G M m}{2 R^2}$

$\frac{G M m}{2 R^2}+m \omega^2 R$

$\frac{G M m}{R^2}-m \omega^2 R$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

A hole is drilled half way to the centre of the earth. A body weighs 300 N on the surface of the earth. How much will, it weigh at the bottom of the hole?

200 N

250 N

120 N

150 N

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