1
JEE Advanced 2019 Paper 1 Offline
Numerical
+3
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A block of weight 100 N is suspended by copper and steel wires of same cross-sectional area 0.5 cm2 and length $$\sqrt 3 $$ m and 1 m, respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are 30$$^\circ $$ and 60$$^\circ $$, respectively. If elongation in copper wire is ($$\Delta {l_c}$$) and elongation in steel wire is ($$\Delta {l_s}$$), then the ratio $${{\Delta {l_c}} \over {\Delta {l_s}}}$$ is .............. .

[Young's modulus for copper and steel are 1 $$ \times $$ 1011 N/m2 and 2 $$ \times $$ 1011 N/m2 respectively.]

JEE Advanced 2019 Paper 1 Offline Physics - Properties of Matter Question 29 English
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2
JEE Advanced 2019 Paper 1 Offline
Numerical
+3
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A liquid at 30$$^\circ $$C is poured very slowly into a Calorimeter that is at temperature of 110$$^\circ $$C. The boiling temperature of the liquid is 80$$^\circ $$C. It is found that the first 5 gm of the liquid completely evaporates. After pouring another 80 gm of the liquid the equilibrium temperature is found to be 50$$^\circ $$C. The ratio of the latent heat of the liquid to its specific heat will be ...........$$^\circ $$C.

[Neglect the heat exchange with surrounding]
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3
JEE Advanced 2018 Paper 1 Offline
Numerical
+3
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Two conducting cylinders of equal length but different radii are connected in series between two heat baths kept at temperatures $${T_1} = 300\,K$$ and $${T_2} = 100\,K$$, as shown in the figure. The radius of the bigger cylinder is twice that of the smaller once and the thermal conductivities of the materials of the smaller and the larger cylinders are $${K_1}$$ and $${K_2}$$ respectively. If the temperature at the junction of the two cylinders in the steady state is $$200$$ $$K,$$ then $${K_1}/{K_2} = $$ ______________.

JEE Advanced 2018 Paper 1 Offline Physics - Properties of Matter Question 38 English
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4
JEE Advanced 2017 Paper 1 Offline
Numerical
+3
-0
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A drop of liquid of radius $$R = {10^{ - 2}}\,m$$ having surface tension $$S = {{0.1} \over {4\pi }}N{m^{ - 1}}$$ divides itself into $$K$$ identical drops. In this process the total change in the surface energy $$\Delta U = {10^{ - 3}}\,J.$$ If $$K = {10^\alpha }$$ then the value of $$\alpha $$ is
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