1
JEE Advanced 2024 Paper 2 Online
MCQ (More than One Correct Answer)
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An aqueous solution of hydrazine $\left(\mathrm{N}_2 \mathrm{H}_4\right)$ is electrochemically oxidized by $\mathrm{O}_2$, thereby releasing chemical energy in the form of electrical energy. One of the products generated from the electrochemical reaction is $\mathrm{N}_2(\mathrm{~g})$.

Choose the correct statement(s) about the above process

A
$\mathrm{OH}^{-}$ions react with $\mathrm{N}_2 \mathrm{H}_4$ at the anode to form $\mathrm{N}_2(\mathrm{~g})$ and water, releasing 4 electrons to the anode.
B
At the cathode, $\mathrm{N}_2 \mathrm{H}_4$ breaks to $\mathrm{N}_2(\mathrm{~g})$ and nascent hydrogen released at the electrode reacts with oxygen to form water.
C
At the cathode, molecular oxygen gets converted to $\mathrm{OH}^{-}$.
D
Oxides of nitrogen are major by-products of the electrochemical process.
2
JEE Advanced 2024 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-2
Change Language

The option(s) with correct sequence of reagents for the conversion of $\mathbf{P}$ to $\mathbf{Q}$ is(are)

JEE Advanced 2024 Paper 2 Online Chemistry - Compounds Containing Nitrogen Question 6 English
A

i) Lindlar's catalyst, $\mathrm{H}_2$;

ii) $\mathrm{SnCl}_2 / \mathrm{HCl}$;

iii) $\mathrm{NaBH}_4$;

iv) $\mathrm{H}_3 \mathrm{O}^{+}$

B

i) Lindlar's catalyst, $\mathrm{H}_2$;

ii) $\mathrm{H}_3 \mathrm{O}^{+}$;

iii) $\mathrm{SnCl}_2 / \mathrm{HCl}$;

iv) $\mathrm{NaBH}_4$

C

i) $\mathrm{NaBH}_4$;

ii) $\mathrm{SnCl}_2 / \mathrm{HCl}$;

iii) $\mathrm{H}_3 \mathrm{O}^{+}$;

iv) Lindlar's catalyst, $\mathrm{H}_2$

D

i) Lindlar's catalyst, $\mathrm{H}_2$;

ii) $\mathrm{NaBH}_4$;

iii) $\mathrm{SnCl}_2 / \mathrm{HCl}$;

iv) $\mathrm{H}_3 \mathrm{O}^{+}$

3
JEE Advanced 2024 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-2
Change Language
The compound(s) having peroxide linkage is(are)
A
$\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_7$
B
$\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8$
C
$\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_5$
D
$\mathrm{H}_2 \mathrm{SO}_5$
4
JEE Advanced 2024 Paper 2 Online
Numerical
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To form a complete monolayer of acetic acid on $1 \mathrm{~g}$ of charcoal, $100 \mathrm{~mL}$ of $0.5 \mathrm{M}$ acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, 40 $\mathrm{mL}$ of $1 \mathrm{M} \mathrm{NaOH}$ solution was required. If each molecule of acetic acid occupies $\mathbf{P} \times 10^{-23} \mathrm{~m}^2$ surface area on charcoal, the value of $\mathbf{P}$ is _____.

[Use given data: Surface area of charcoal $=1.5 \times 10^2 \mathrm{~m}^2 \mathrm{~g}^{-1}$; Avogadro's number $\left(\mathrm{N}_{\mathrm{A}}\right)=6.0 \times 10^{23}$ $\left.\mathrm{mol}^{-1}\right]$

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