1
JEE Advanced 2024 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1
Change Language
According to Bohr's model, the highest kinetic energy is associated with the electron in the
A
first orbit of $\mathrm{H}$ atom
B
first orbit of $\mathrm{He}^{+}$
C
second orbit of $\mathrm{He}^{+}$
D
second orbit of $\mathrm{Li}^{2+}$
2
JEE Advanced 2024 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1
Change Language
In a metal deficient oxide sample, $\mathbf{M}_{\mathbf{x}} \mathbf{Y}_2 \mathbf{O}_4$ ( $\mathbf{M}$ and $\mathbf{Y}$ are metals), $\mathbf{M}$ is present in both +2 and +3 oxidation states and $\mathbf{Y}$ is in +3 oxidation state. If the fraction of $\mathbf{M}^{2+}$ ions present in $\mathbf{M}$ is $\frac{1}{3}$, the value of $\mathbf{X}$ is _______ .
A
0.25
B
0.33
C
0.67
D
0.75
3
JEE Advanced 2024 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

In the following reaction sequence, the major product $\mathbf{Q}$ is

JEE Advanced 2024 Paper 2 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 6 English
A
JEE Advanced 2024 Paper 2 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 6 English Option 1
B
JEE Advanced 2024 Paper 2 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 6 English Option 2
C
JEE Advanced 2024 Paper 2 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 6 English Option 3
D
JEE Advanced 2024 Paper 2 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 6 English Option 4
4
JEE Advanced 2024 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are

A
$\left[\mathrm{PF}_4\right]^{+}\left[\mathrm{PF}_6\right]^{-}$and $\left[\mathrm{PCl}_4\right]^{+}\left[\mathrm{PF}_6\right]^{-}$
B
$\left[\mathrm{PCl}_4\right]^{+}\left[\mathrm{PCl}_4 \mathrm{~F}_2\right]^{-}$and $\left[\mathrm{PCl}_4\right]^{+}\left[\mathrm{PF}_6\right]^{-}$
C
$\mathrm{PF}_3$ and $\mathrm{PCl}_3$
D
$\mathrm{PF}_5$ and $\mathrm{PCl}_3$
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