1
JEE Advanced 2020 Paper 2 Offline
Numerical
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Two capacitors with capacitance values C1 = 2000 $$ \pm $$ 10 pF and C2 = 3000 $$ \pm $$ 15 pF are connected in series. The voltage applied across this combination is V = 5.00 $$ \pm $$ 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is ________.
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JEE Advanced 2020 Paper 2 Offline
Numerical
+4
-0
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A cubical solid aluminium (bulk modulus = $$ - V{{dP} \over {dV}} = 70GPa$$) block has an edge length of 1 m on the surface of the earth. It is kept on the floor of a 5 km deep ocean. Taking the average density of water and the acceleration due to gravity to be 103 kg m-3 and 10 ms-2, respectively, the change in the edge length of the block in mm is _______.
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3
JEE Advanced 2020 Paper 2 Offline
Numerical
+4
-0
Change Language
The inductors of two LR circuits are placed next to each other, as shown in the figure. The values of the self-inductance of the inductors, resistors, mutual-inductance and applied voltages are specified in the given circuit. After both the switches are closed simultaneously, the total work done by the batteries against the induced EMF in the inductors by the time the currents reach their steady state values is _________ mJ.

JEE Advanced 2020 Paper 2 Offline Physics - Electromagnetic Induction Question 9 English
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4
JEE Advanced 2020 Paper 2 Offline
Numerical
+4
-0
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A container with 1 kg of water in it is kept in sunlight, which causes the water to get warmer than the surroundings. The average energy per unit time per unit area received due to the sunlight is 700 Wm$$-$$2 and it is absorbed by the water over an effective area of 0.05m2. Assuming that the heat loss from the water to the surroundings is governed by Newton's law of cooling, the difference (in $$^\circ$$C) in the temperature of water and the surroundings after a long time will be ___________. (Ignore effect of the container, and take constant for Newton's law of cooling = 0.001 s$$-$$1, Heat capacity of water = 4200 J kg$$-$$1 K$$-$$1)
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