1
JEE Advanced 2020 Paper 2 Offline
MCQ (More than One Correct Answer)
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-2
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Consider the following transformations of a compound P.

JEE Advanced 2020 Paper 2 Offline Chemistry - Hydrocarbons Question 20 English

Choose the correct option(s).
A
P is

JEE Advanced 2020 Paper 2 Offline Chemistry - Hydrocarbons Question 20 English Option 1
B
X is Pd-C/quinoline/H2
C
P is

JEE Advanced 2020 Paper 2 Offline Chemistry - Hydrocarbons Question 20 English Option 3
D
R is

JEE Advanced 2020 Paper 2 Offline Chemistry - Hydrocarbons Question 20 English Option 4
2
JEE Advanced 2020 Paper 2 Offline
Numerical
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A solution of 0.1 M weak base (B) is titrated with 0.1 M of a strong acid (HA). The variation of pH of the solution with the volume of HA added is shown in the figure below. What is the pKb of the base? The neutralisation reaction is given by

$$B + HA\buildrel {} \over \longrightarrow B{H^ + } + {A^ - }$$

JEE Advanced 2020 Paper 2 Offline Chemistry - Ionic Equilibrium Question 7 English
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3
JEE Advanced 2020 Paper 2 Offline
Numerical
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Liquids A and B form ideal solution for all compositions of A and B at 25$$^\circ $$C. Two such solutions with 0.25 and 0.50 mole fractions of A have the total vapour pressure of 0.3 and 0.4 bar, respectively. What is the vapour pressure of pure liquid B in bar?
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4
JEE Advanced 2020 Paper 2 Offline
Numerical
+4
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The figure below is the plot of potential energy versus internuclear distance (d) of H2 molecule in the electronic ground state. What is the value of the net potential energy E0 (as indicated in the figure) in kJ mol-1, for d = d0 at which the electron-electron repulsion and the nucleus-nucleus repulsion energies are absent? As reference, the potential energy of H atom is taken as zero when its electron and the nucleus are infinitely far apart.
Use Avogadro constant as 6.023 $$ \times $$ 1023 mol-1.

JEE Advanced 2020 Paper 2 Offline Chemistry - Structure of Atom Question 6 English
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