1
JEE Advanced 2019 Paper 1 Offline
Numerical
+3
-0
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On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 mmHg to 640 mmHg. The depression of freezing point of benzene (in K) upon addition of the solute is .............

(Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol-1 and 5.12 K kg mol-1, respectively).
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2
JEE Advanced 2019 Paper 1 Offline
Numerical
+3
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Consider the kinetic data given in the following table for the reaction A + B + C $$ \to $$ Product.

JEE Advanced 2019 Paper 1 Offline Chemistry - Chemical Kinetics and Nuclear Chemistry Question 13 English
The rate of the reaction for [A] = 0.15 mol dm-3, [B] = 0.25 mol dm-3 and [C] = 0.15 mol dm-3 is found to be Y $$ \times $$ 10-5 mol dm-3s-1. The value of Y is .................
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3
JEE Advanced 2019 Paper 1 Offline
Numerical
+3
-0
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For the following reaction, the equilibrium constant Kc at 298 K is 1.6 $$ \times $$ 1017.

Fe2+(aq) + S2-(aq) ⇌ FeS(s)

When equal volumes of

0.06 M Fe2+(aq) and 0.2 M S2$$ - $$(aq)

solutions are mixed, the equilibrium concentration of Fe2+(aq) is found by Y $$ \times $$ 10$$ - $$17 M. The value of Y is .................
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4
JEE Advanced 2019 Paper 1 Offline
Numerical
+3
-0
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At 143 K, the reaction of XeF4 with O2F2 produces a xenon compound Y. The total number of lone pair(s) of electrons present on the whole molecule of Y is .................
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