1
JEE Advanced 2019 Paper 1 Offline
Numerical
+3
-0
Change Language
At 143 K, the reaction of XeF4 with O2F2 produces a xenon compound Y. The total number of lone pair(s) of electrons present on the whole molecule of Y is .................
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2
JEE Advanced 2019 Paper 1 Offline
Numerical
+3
-0
Change Language
Schemes 1 and 2 describe the conversion of P to Q and R to S, respectively. Scheme 3 describes the synthesis of T from Q and S. The total number of Br atoms in a molecule of T is .................

JEE Advanced 2019 Paper 1 Offline Chemistry - Compounds Containing Nitrogen Question 26 English
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3
JEE Advanced 2019 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
Let S be the set of all complex numbers z satisfying $$\left| {z - 2 + i} \right| \ge \sqrt 5 $$. If the complex number z0 is such that $${1 \over {\left| {{z_0} - 1} \right|}}$$ is the maximum of the set $$\left\{ {{1 \over {\left| {{z_0} - 1} \right|}}:z \in S} \right\}$$, then the principal argument of $${{4 - {z_0} - {{\overline z }_0}} \over {{z_0} - {{\overline z }_0} + 2i}}$$ is
A
$${\pi \over 4}$$
B
$${3\pi \over 4}$$
C
$$ - $$$${\pi \over 2}$$
D
$${\pi \over 2}$$
4
JEE Advanced 2019 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
Let $$M = \left[ {\matrix{ {{{\sin }^4}\theta } \cr {1 + {{\cos }^2}\theta } \cr } \matrix{ { - 1 - {{\sin }^2}\theta } \cr {{{\cos }^4}\theta } \cr } } \right] = \alpha I + \beta {M^{ - 1}}$$,

where $$\alpha $$ = $$\alpha $$($$\theta $$) and $$\beta $$ = $$\beta $$($$\theta $$) are real numbers, and I is the 2 $$ \times $$ 2 identity matrix. If $$\alpha $$* is the minimum of the set {$$\alpha $$($$\theta $$) : $$\theta $$ $$ \in $$ [0, 2$$\pi $$)} and {$$\beta $$($$\theta $$) : $$\theta $$ $$ \in $$ [0, 2$$\pi $$)}, then the value of $$\alpha $$* + $$\beta $$* is
A
$$ - {{17} \over {16}}$$
B
$$ - {{31} \over {16}}$$
C
$$ - {{37} \over {16}}$$
D
$$ - {{29} \over {16}}$$
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