1
IIT-JEE 2010 Paper 2 Offline
+3
-0.75
When liquid medicine of density $$\rho$$ is to be put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from the dropper.

If r = 5 $$\times$$ 10−4 m, $$\rho$$ = 103 kg m−3 , g = 10 m/s2 , T = 0.11 Nm−1 , the radius of the drop when it detaches from the dropper is approximately

A
1.4 $$\times$$ 10−3 m
B
3.3 $$\times$$ 10−3 m
C
2.0 $$\times$$ 10−3 m
D
4.1 $$\times$$ 10−3 m
2
IIT-JEE 2010 Paper 2 Offline
+3
-0.75
When liquid medicine of density $$\rho$$ is to be put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from the dropper.

After the drop detaches, its surface energy is

A
1.4 $$\times$$ 10−6 J
B
2.7 $$\times$$ 10−6 J
C
5.4 $$\times$$ 10−6 J
D
8.1 $$\times$$ 10−6 J
3
IIT-JEE 2008 Paper 2 Offline
+3
-1

A glass tube of uniform internal radius (r) has a valve separating the two identical ends. Initially, the valve is in a tightly closed position. End 1 has a hemispherical soap bubble of radius r. End 2 has sub-hemispherical soap bubble as shown in figure. Just after opening the valve,

A
air from end 1 flows towards end 2. No change in the volume of the soap bubbles
B
air from end 1 flows towards end 2. Volume of the soap bubble at end 1 decreases
C
no change occurs
D
air from end 2 flows towards end 1. Volume of the soap bubble at end 1 increases
4
IIT-JEE 2008 Paper 1 Offline
+3
-1

STATEMENT - 1 :

The stream of water flowing at high speed from a garden hose pipe tends to spread line a fountain when held vertically up, but tends to narrow down when held vertically down.

and

STATEMENT - 2 :

In any steady flow of an incompressible fluid, the volume flow rate of the fluid remains constant.

A
Statement - 1 is True, Statement - 2 is True; Statement - 2 is a correct explanation for Statement - 1
B
Statement - 1 is True, Statement - 2 is True; Statement - 2 is NOT a correct explanation for Statement - 1
C
Statement - 1 is True, Statement - 2 is False
D
Statement - 1 is False, Statement - 2 is True
EXAM MAP
Medical
NEET