JEE Advanced 2013 Paper 2 Offline

MCQ (More than One Correct Answer)

-0.75

Using the expression $$2d\sin \theta = \lambda $$, one calculates the values of d by measuring the corresponding angles $$\theta $$ in the range 0 to 90^o. The wavelength $$\lambda $$ is exactly known and the error in $$\theta $$ is constant for all values of $$\theta $$. As $$\theta $$ increases from 0^o

the absolute error in d remains constant

the absolute error in d increases

the fractional error in d remains constant

the fractional error in d decreases

IIT-JEE 2006

MCQ (More than One Correct Answer)

-1

The graph between $\frac{1}{\lambda}$ and stopping potential (V) of three metals having work functions $\phi_1, \phi_2$, and $\phi_3$ in an experiment of photoelectric effect is plotted as shown in the figure. Which of the following statement(s) is/are correct? (Here, $\lambda$ is the wavelength of the incident ray).

IIT-JEE 2006 Physics - Dual Nature of Radiation Question 1 English

Ratio of work functions $\phi_1: \phi_2: \phi_3 =1: 2: 4$.

Ratio of work functional $\phi_1: \phi_2: \phi_3 =4: 2: 1$.

$\tan \theta$ is directly proportional to $\frac{h c}{e}$, where $h$ is Planck's constant and $c$ is the speed of light.

The violet colour light can eject photoelectrons from metals 2 and 3 .

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