For photo-electric effect with incident photon wavelength $$\lambda$$, the stopping potential is V₀. Identify the correct variation(s) of V₀ with $$\lambda$$ and $${1 \over \lambda }$$.

Using the expression $$2d\sin \theta = \lambda $$, one calculates the values of d by measuring the corresponding angles $$\theta $$ in the range 0 to 90^o. The wavelength $$\lambda $$ is exactly known and the error in $$\theta $$ is constant for all values of $$\theta $$. As $$\theta $$ increases from 0^o