1
JEE Advanced 2020 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
Change Language
Shown in the figure is a semicircular metallic strip that has thickness t and resistivity $$\rho $$. Its inner radius is R1 and outer radius is R2. If a voltage V0 is applied between its two ends, a current I flows in it. In addition, it is observed that a transverse voltage $$\Delta $$V develops between its inner and outer surfaces due to purely kinetic effects of moving electrons (ignore any role of the magnetic field due to the current). Then (figure is schematic and not drawn to scale) JEE Advanced 2020 Paper 1 Offline Physics - Current Electricity Question 31 English
A
$$I = {{{V_0}t} \over {\pi \rho }}\ln \left( {{{{R_2}} \over {{R_1}}}} \right)$$
B
the outer surface is at a higher voltage than the inner surface
C
the outer surface is at a lower voltage than the inner surface
D
$$\Delta $$V $$ \propto $$ I2
2
JEE Advanced 2019 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
In the circuit shown, initially there is no charge on the capacitors and keys S1 and S2 are open. The values of the capacitors are C1 = 10$$\mu $$F, C2 = 30$$\mu $$F and C3 = C4 = 80$$\mu $$F.

JEE Advanced 2019 Paper 1 Offline Physics - Current Electricity Question 30 English

Which of the statement(s) is/are correct?
A
The key S1 is kept closed for long time such that capacitors are fully charged. Now, key S2 is closed, at this time, the instantaneous current across 30$$\Omega $$ resistor (between points P and Q) will be 0.2 A (round off to 1st decimal place).
B
If key S1 is kept closed for long time such that capacitors are fully charged, the voltage across the capacitor C1 will be 4V.
C
At time t = 0, the key S1 is closed, the instantaneous current in the closed circuit will be 25 mA.
D
If key S1 is kept closed for long time such that the capacitors are fully charged, the voltage difference between points P and Q will be 10 V.
3
JEE Advanced 2019 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
A charged shell of radius R carries a total charge Q. Given $$\phi $$ as the flux of electric field through a closed cylindrical surface of height h, radius r and with its center same as that of the shell. Here, center of the cylinder is a point on the axis of the cylinder which is equidistant from its top and bottom surfaces. Which of the following option(s) is/are correct?

[$$ \in $$0 is the permittivity of free space]
A
If h > 2R and r = 4R / 5 then $$\phi $$ = Q / 5 $$ \in $$0
B
If h > 2R and r = 3R / 5 then $$\phi $$ = Q / 5 $$ \in $$0
C
If h > 8R /5 and r = 3R / 5 then $$\phi $$ = 0
D
If h > 2R and r = R then $$\phi $$ = Q / $$ \in $$0
4
JEE Advanced 2019 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
Two identical moving coil galvanometers have 10$$\Omega $$ resistance and full scale deflection at 2$$\mu $$A current. One of them is converted into a voltmeter of 100 mV full scale reading and the other into an ammeter of 1 mA full scale current using appropriate resistors. These are then used to measure the voltage and current in the Ohm's law experiment with R = 1000$$\Omega $$ resistor by using an ideal cell. Which of the following statement(s) is/are correct?
A
The resistance of the voltmeter will be 100 k$$\Omega $$.
B
The resistance of the ammeter will be 0.02 $$\Omega $$

(round off to 2nd decimal place).
C
If the ideal cell is replaced by a cell having internal resistance of 5$$\Omega $$ then the measured value of R will be more than 1000$$\Omega $$.
D
The measured value of R will be 978$$\Omega $$ < R < 982$$\Omega $$.
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