IIT-JEE 2009 Paper 1 Offline | Current Electricity Question 29 | Physics

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IIT-JEE 2009 Paper 1 Offline

MCQ (More than One Correct Answer)

-2

For the circuit shown in the figure

IIT-JEE 2009 Paper 1 Offline Physics - Current Electricity Question 9 English

The current I through the battery is 7.5 mA.

The potential difference across $$R_L$$, is 18 V.

Ratio of powers dissipated in $$R_1$$ and $$R_2$$ is 3.

If $$R_1$$ and $$R_2$$ are interchanged, magnitude of the power dissipated in $$R_L$$ will decrease by a factor of 9.

IIT-JEE 2006

MCQ (More than One Correct Answer)

-1

In the given diagram, a line of force of a particular force field is shown. Out of the following options, it can never represent

an electrostatic field.

a magnetostatic field.

a gravitational field of a mass at rest.

an induced electric field

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