1
MHT CET 2024 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

When photons of energy hv fall on a photosensitive surface of work function $\mathrm{E}_0$, photoelectrons of maximum energy $k$ are emitted. If the frequency of radiation is doubled the maximum kinetic energy will be equal to ( $\mathrm{h}=$ Planck's constant)

A
k
B
2 k
C
$\mathrm{k}+\mathrm{E}_0$
D
$\mathrm{k}+\mathrm{h} \nu$
2
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The number of photoelectrons emitted for light of frequency $v$ (higher than the threshold frequency $\left(v_0\right)$ is proportional to

A
threshold frequency $\left(v_0\right)$
B
intensity of light (I)
C
frequency of light (v)
D
work function $\left(\phi_0\right)$
3
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The stopping potential for a photelectric emission process is 10 V . The maximum kinetic energy of the electrons ejected in the process is [Charge on electron $\mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$ ]

A
$3.2 \times 10^{-19} \mathrm{~J}$
B
$1.6 \times 10^{-19} \mathrm{~J}$
C
$1.6 \times 10^{-18} \mathrm{~J}$
D
0 J
4
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

When a metallic surface is illuminated with a radiation of wavelength ' $\lambda$ ', the stopping potential is ' $V$ '. If the same surface is illuminated with radiation of wavelength ' $3 \lambda$ ', the stopping potential is ' $\left(\frac{\mathrm{V}}{6}\right)$ '. The threshold wavelength for the surface is

A
$3 \lambda$
B
$4 \lambda$
C
$5 \lambda$
D
$6 \lambda$
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