1
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Change Language
Pure water freezes at $$273$$ $$K$$ and $$1$$ bar. The addition of $$34.5$$ $$g$$ of ethanol to $$500$$ $$g$$ of water changes the freezing point of the solution. Use the freezing point depression constant of water as $$2$$ kg $$mo{l^{ - 1}}.$$ The figures shown below represent plots of vapor pressure $$(V.P.)$$ versus temperature $$(T).$$ [molecular weight of ethanol is $$46$$ $$g$$ $$mo{l^{ - 1}}.$$ ] Among the following, the option representing change in the freezing point is
A
JEE Advanced 2017 Paper 2 Offline Chemistry - Solutions Question 13 English Option 1
B
JEE Advanced 2017 Paper 2 Offline Chemistry - Solutions Question 13 English Option 2
C
JEE Advanced 2017 Paper 2 Offline Chemistry - Solutions Question 13 English Option 3
D
JEE Advanced 2017 Paper 2 Offline Chemistry - Solutions Question 13 English Option 4
2
JEE Advanced 2016 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language

The qualitative sketches I, II and III given below show the variation of surface tension with molar concentration of three different aqueous solutions of KCl, CH3OH and CH3(CH2)11 OSO$$_3^ - $$ Na+ at room temperature. The correct assignment of the sketches is

JEE Advanced 2016 Paper 2 Offline Chemistry - Solutions Question 8 English

A

I : KCl

II : CH3OH

III : CH3(CH2)11 OSO$$_3^ - $$ Na+

B

I. CH3(CH2)11 OSO$$_3^ - $$ Na+

II. CH3OH

III. KCl

C

I. KCl

II. CH3(CH2)11 OSO$$_3^ - $$ Na+

III. CH3OH

D

I. CH3OH

II. KCl

III. CH3(CH2)11 OSO$$_3^ - $$ Na+

3
IIT-JEE 2012 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solute in 100 g of water. the elevation in boiling point at 1 atm pressure is 2oC. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is (take Kb = 0.76 K Kg mol-1)
A
724
B
780
C
736
D
718
4
IIT-JEE 2011 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
The freezing point (in oC) of a solution containing 0.1 g of K3[Fe(CN)6] (Mol. wt. 329) in 100 g of water (Kf = 1.86 K kg mol-1) is
A
-2.3 $$\times$$ 10-2
B
-5.7 $$\times$$ 10-2
C
-5.7 $$\times$$ 10-3
D
-1.2 $$\times$$ 10-2
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