JEE Advanced 2016 Paper 2 Offline | Solutions Question 17 | Chemistry

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JEE Advanced 2016 Paper 2 Offline

MCQ (Single Correct Answer)

-1

The qualitative sketches I, II and III given below show the variation of surface tension with molar concentration of three different aqueous solutions of KCl, CH₃OH and CH₃(CH₂)₁₁ OSO$$_3^ - $$ Na⁺ at room temperature. The correct assignment of the sketches is

JEE Advanced 2016 Paper 2 Offline Chemistry - Solutions Question 13 English

I : KCl

II : CH₃OH

III : CH₃(CH₂)₁₁ OSO$$_3^ - $$ Na⁺

I. CH₃(CH₂)₁₁ OSO$$_3^ - $$ Na⁺

II. CH₃OH

III. KCl

I. KCl

II. CH₃(CH₂)₁₁ OSO$$_3^ - $$ Na⁺

III. CH₃OH

I. CH₃OH

II. KCl

III. CH₃(CH₂)₁₁ OSO$$_3^ - $$ Na⁺

IIT-JEE 2012 Paper 2 Offline

MCQ (Single Correct Answer)

-0.75

For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solute in 100 g of water. the elevation in boiling point at 1 atm pressure is 2^oC. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is (take K_b = 0.76 K Kg mol^-1)

724

780

736

718

IIT-JEE 2011 Paper 2 Offline

MCQ (Single Correct Answer)

-0.75

The freezing point (in ^oC) of a solution containing 0.1 g of K₃[Fe(CN)₆] (Mol. wt. 329) in 100 g of water (K_f = 1.86 K kg mol^-1) is

-2.3 $$\times$$ 10^-2

-5.7 $$\times$$ 10^-2

-5.7 $$\times$$ 10^-3

-1.2 $$\times$$ 10^-2

IIT-JEE 2009 Paper 1 Offline

MCQ (Single Correct Answer)

-1

The Henry's law constant for the solubility of N$$_2$$ gas in water at 298 K is 1.0 $$\times$$ 10$$^5$$ atm. The mole fraction of N$$_2$$ in air is 0.8. The number of moles of N$$_2$$ from air dissolved in 10 moles of water at 298 K and 5 atm pressure is

4.0 $$\times$$ 10$$^{-4}$$

4.0 $$\times$$ 10$$^{-5}$$

5.0 $$\times$$ 10$$^{-4}$$

4.0 $$\times$$ 10$$^{-6}$$

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