MHT CET 2023 14th May Morning Shift | Gravitation Question 4 | Physics

The value of acceleration due to gravity at a depth '$$d$$' from the surface of earth and at an altitude '$$h$$' from the surface of earth are in the ratio

$$1: 1$$

$$\frac{R-2 h}{R-d}$$

$$\frac{R-d}{R-2 h}$$

$$\frac{\mathrm{R}-\mathrm{d}}{\mathrm{R}-\mathrm{h}}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

If two planets have their radii in the ratio $$x: y$$ and densities in the ratio $$m: n$$, then the acceleration due to gravity on them are in the ratio

$$\frac{n y}{m x}$$

$$\frac{m y}{n x}$$

$$\frac{n x}{m y}$$

$$\frac{m x}{n y}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

A mine is located at depth $$R / 3$$ below earth's surface. The acceleration due to gravity at that depth in mine is ($$R=$$ radius of earth, $$g=$$ acceleration due to gravity)

$$g$$

$$3 g$$

$$\frac{2 g}{3}$$

$$\frac{g}{3}$$

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

-0

A body of mass '$$\mathrm{m}$$' is raised through a height above the earth's surface so that the increase in potential energy is $$\frac{\mathrm{mgR}}{5}$$. The height to which the body is raised is ( $$\mathrm{R}=$$ radius of earth, $$\mathrm{g}=$$ acceleration due to gravity)

$$\mathrm{R}$$

$$\frac{\mathrm{R}}{2}$$

$$\frac{\mathrm{R}}{4}$$

$$\frac{\mathrm{R}}{8}$$

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