P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorise Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.
In the following reaction sequences V and W are, respectively,
Match the chemical conversations in List I with the appropriate reagents in List II and select the correct answer using the code given below the lists :
The compound that does NOT liberate CO2, on treatment with aqueous sodium bicarbonate solution, is
The major product H of the given reaction sequence is
$$C{H_3} - C{H_2} - CO - C{H_3}\buildrel {\overline C N} \over \longrightarrow G\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{Heat}^{95\% \,{H_2}S{O_4}}} H$$
