1
JEE Advanced 2018 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-0.75
Change Language
An organic acid P $$\left( {{C_{11}}{H_{12}}{O_2}} \right)$$ can easily be oxidized to a dibasic acid which reacts with ethylene glycol to produce a polymer dacron. Upon ozonolysis, P gives an aliphatic ketone as one of the products. P undergoes the following reaction sequences to furnish R via Q. The compound P also undergoes another set of reactions to produce S.

JEE Advanced 2018 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 66 English

The compound S is
A
JEE Advanced 2018 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 66 English Option 1
B
JEE Advanced 2018 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 66 English Option 2
C
JEE Advanced 2018 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 66 English Option 3
D
JEE Advanced 2018 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 66 English Option 4
2
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Change Language
The reaction of compound $$P$$ with $$C{H_3}MgBr$$ (excess) in $${\left( {{C_2}{H_5}} \right)_2}O$$ followed by addition of $${H_2}O$$ gives $$Q.$$ The compound $$Q$$ on treatment with $${H_2}S{O_4}$$ at $${0^ \circ }C$$ gives $$R.$$ The reaction of $$R$$ with $$C{H_3}COCl$$ in the presence of anhydrous $$AlC{l_3}$$ in $$C{H_2}C{l_2}$$ followed by treatment with $${H_2}O$$ producess compound $$S.$$ [$$Et$$ in compound $$P$$ is ethyl group]

JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 58 English Comprehension
The reactions, $$Q$$ to $$R$$ and $$R$$ to $$S,$$ are
A
Dehydration and Friedel$$-$$Crafts acylation
B
Aromatic sulfonation and Friedel$$-$$Crafts acylation
C
Friedel$$-$$Crafts alkylation, dehydration and Friedel$$-$$Crafts acylation
D
Friedel$$-$$Crafts alkylation and Friedel$$-$$Crafts acylation
3
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Change Language
The reaction of compound $$P$$ with $$C{H_3}MgBr$$ (excess) in $${\left( {{C_2}{H_5}} \right)_2}O$$ followed by addition of $${H_2}O$$ gives $$Q.$$ The compound $$Q$$ on treatment with $${H_2}S{O_4}$$ at $${0^ \circ }C$$ gives $$R.$$ The reaction of $$R$$ with $$C{H_3}COCl$$ in the presence of anhydrous $$AlC{l_3}$$ in $$C{H_2}C{l_2}$$ followed by treatment with $${H_2}O$$ producess compound $$S.$$ [$$Et$$ in compound $$P$$ is ethyl group]

JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Comprehension
The product $$S$$ is
A
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Option 1
B
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Option 2
C
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Option 3
D
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Option 4
4
JEE Advanced 2017 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK
(R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
For the synthesis of benzoic acid, the only CORRECT combination is
A
(II) (i) (S)
B
(IV) (ii) (P)
C
(I) (iv) (Q)
D
(III) (iv) (R)
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