1
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Change Language
The reaction of compound $$P$$ with $$C{H_3}MgBr$$ (excess) in $${\left( {{C_2}{H_5}} \right)_2}O$$ followed by addition of $${H_2}O$$ gives $$Q.$$ The compound $$Q$$ on treatment with $${H_2}S{O_4}$$ at $${0^ \circ }C$$ gives $$R.$$ The reaction of $$R$$ with $$C{H_3}COCl$$ in the presence of anhydrous $$AlC{l_3}$$ in $$C{H_2}C{l_2}$$ followed by treatment with $${H_2}O$$ producess compound $$S.$$ [$$Et$$ in compound $$P$$ is ethyl group]

JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Comprehension
The product $$S$$ is
A
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Option 1
B
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Option 2
C
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Option 3
D
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English Option 4
2
JEE Advanced 2017 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK
(R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
For the synthesis of benzoic acid, the only CORRECT combination is
A
(II) (i) (S)
B
(IV) (ii) (P)
C
(I) (iv) (Q)
D
(III) (iv) (R)
3
JEE Advanced 2017 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK
(R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
The only CORRECT combination in which the reaction proceeds through radical mechanism is :
A
(III) (ii) (P)
B
(IV) (i) (Q)
C
(II) (iii) (R)
D
(I) (ii) (R)
4
JEE Advanced 2017 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

Column 1 Column 2 Column 3
(I) Toluene (i) NaOH/Br2 (P) Condensation
(II) Acetophenone (ii) Br2/hv (Q) Carboxylation
(III) Benzaldehyde (iii) (CH3CO)2O/
CH3COOK
(R) Substitution
(IV) Phenol (iv) NaOH/CO2 (S) Haloform
The only CORRECT combination that gives two different carboxylic acids is :
A
(II) (iv) (R)
B
(IV) (iii) (Q)
C
(III) (iii) (P)
D
(I) (i) (S)
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