MHT CET 2021 24th September Evening Shift | Dual Nature of Radiation Question 56 | Physics

In a photoelectric experiment, a graph of maximum kinetic energy $$(\mathrm{KE}_{\text {max }})$$ against the frequency of incident radiation (v) is plotted. If $$\mathrm{A}$$ and $$\mathrm{B}$$ are the intercepts on the $$\mathrm{X}$$ and $$\mathrm{Y}$$ axis respectively then the Planck's constant is given by

$$\mathrm{A}+\mathrm{B}$$

$$\frac{B}{A^{\prime}}$$

$$\mathrm{A} \times \mathrm{B}$$

$$\frac{\mathrm{A}}{\mathrm{B}}$$

MHT CET 2021 24th September Morning Shift

MCQ (Single Correct Answer)

-0

A photon has wavelength $$3 \mathrm{~nm}$$, then its momentum and energy respectively will be $$[\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}, \mathrm{c}=$$ velocity of light $$=3 \times 10^8 \mathrm{~m} / \mathrm{s}]$$

$$2.21 \times 10^{-43} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 \times 10^{-34} \mathrm{~J}$$

$$2.21 \times 10^{-34} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 \times 10^{-25} \mathrm{~J}$$

$$2.21 \times 10^{-25} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 \times 10^{-17} \mathrm{~J}$$

$$2.21 \times 10^{-16} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 \times 10^{-19} \mathrm{~J}$$

MHT CET 2021 24th September Morning Shift

MCQ (Single Correct Answer)

-0

In photoelectric experiment keeping the frequency of incident radiation and accelerating potential fixed, if the intensity of incident light is increased,

photoelectric current decreases

kinetic energy of emitted photoelectrons decreases

photoelectric current increases

kinetic energy of emitted photoelectrons increases

MHT CET 2021 23rd September Evening Shift

MCQ (Single Correct Answer)

-0

de-Broglie wavelength associated with an electron accelerated through a potential difference '$$\mathrm{V}$$' is '$$\lambda$$'. When the accelerating potential is increased to '$$4 \mathrm{~V}$$', de-Broglie wavelength.

reduces to half

remains the same

reduces to $$(1 / 4)^{\text {th }}$$

increases by $$25 \%$$

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