1
MHT CET 2021 24th September Evening Shift
+1
-0

In a photoelectric experiment, a graph of maximum kinetic energy $$(\mathrm{KE}_{\text {max }})$$ against the frequency of incident radiation (v) is plotted. If $$\mathrm{A}$$ and $$\mathrm{B}$$ are the intercepts on the $$\mathrm{X}$$ and $$\mathrm{Y}$$ axis respectively then the Planck's constant is given by

A
$$\mathrm{A}+\mathrm{B}$$
B
$$\frac{B}{A^{\prime}}$$
C
$$\mathrm{A} \times \mathrm{B}$$
D
$$\frac{\mathrm{A}}{\mathrm{B}}$$
2
MHT CET 2021 24th September Morning Shift
+1
-0

A photon has wavelength $$3 \mathrm{~nm}$$, then its momentum and energy respectively will be $$[\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}, \mathrm{c}=$$ velocity of light $$=3 \times 10^8 \mathrm{~m} / \mathrm{s}]$$

A
$$2.21 \times 10^{-43} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 \times 10^{-34} \mathrm{~J}$$
B
$$2.21 \times 10^{-34} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 \times 10^{-25} \mathrm{~J}$$
C
$$2.21 \times 10^{-25} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 \times 10^{-17} \mathrm{~J}$$
D
$$2.21 \times 10^{-16} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 \times 10^{-19} \mathrm{~J}$$
3
MHT CET 2021 24th September Morning Shift
+1
-0

In photoelectric experiment keeping the frequency of incident radiation and accelerating potential fixed, if the intensity of incident light is increased,

A
photoelectric current decreases
B
kinetic energy of emitted photoelectrons decreases
C
photoelectric current increases
D
kinetic energy of emitted photoelectrons increases
4
MHT CET 2021 23rd September Evening Shift
+1
-0

de-Broglie wavelength associated with an electron accelerated through a potential difference '$$\mathrm{V}$$' is '$$\lambda$$'. When the accelerating potential is increased to '$$4 \mathrm{~V}$$', de-Broglie wavelength.

A
reduces to half
B
remains the same
C
reduces to $$(1 / 4)^{\text {th }}$$
D
increases by $$25 \%$$
EXAM MAP
Medical
NEET