1
MHT CET 2024 15th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $y=\frac{x^{\frac{2}{3}}-x^{\frac{-1}{3}}}{x^{\frac{2}{3}}+x^{\frac{-1}{3}}}, x \neq 0$, then $(x+1)^2 y_1=$

A
2
B
$-$2
C
$\frac{-1}{3}$
D
3
2
MHT CET 2024 15th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The derivative of $\sin ^{-1}\left(2 x \sqrt{1-x^2}\right)$ w.r.t. $\sin ^{-1}\left(3 x-4 x^3\right)$ is

A
$\frac{2}{3}$
B
$\frac{1}{2}$
C
$\frac{3}{2}$
D
$1$
3
MHT CET 2024 15th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $f(1)=1, f^{\prime}(1)=3$, then the derivative of $\mathrm{f}(\mathrm{f}(\mathrm{f}(x)))+(\mathrm{f}(x))^2$ at $x=1$ is

A
12
B
30
C
15
D
33
4
MHT CET 2024 15th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$ y=[(x+1)(2 x+1)(3 x+1) \ldots \ldots \ldots(n x+1)]^2 $$ then $\frac{\mathrm{d} y}{\mathrm{~d} x}$ at $x=0$ is

A
$2 \mathrm{n}(\mathrm{n}+1)$
B
$\mathrm{n}(\mathrm{n}+1)$
C
 $\frac{\mathrm{n}(\mathrm{n}+1)}{2}$
D
$\left(\frac{\mathrm{n}(\mathrm{n}+1)}{2}\right)^2$
MHT CET Subjects
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