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1
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
For $\mathrm{n} \in \mathbb{N}$ if $y=\mathrm{a} x^{\mathrm{n}+1}+\mathrm{b} x^{-\mathrm{n}}$, then $x^2 \frac{\mathrm{~d}^2 y}{\mathrm{~d} x^2}=$
A
$\mathrm{n}(\mathrm{n}-1) y$
B
$(\mathrm{n}-1) y$
C
$\mathrm{n}(\mathrm{n}+1) y$
D
$(\mathrm{n}+1) y$
2
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The derivative of $\tan ^{-1}\left(\sqrt{1+x^2}-1\right)$ is
A
$\frac{x}{\sqrt{1+x^2}\left(x^2-2 \sqrt{x+1}+1\right)}$
B
$\frac{x}{\sqrt{1+x^2}\left(x^2-2 \sqrt{1+x^2}+3\right)}$
C
$\frac{x}{\sqrt{1+x^2}\left(x^2-2 \sqrt{x^2+1}+2\right)}$
D
$\frac{x}{\sqrt{1+x^2}\left(x^2+2 \sqrt{1+x^2}-3\right)}$
3
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{g}(x)=[\mathrm{f}(2 \mathrm{f}(x)+2)]^2$ and $\mathrm{f}(0)=-1, \mathrm{f}^{\prime}(0)=1$ then $g^{\prime}(0)$ is

A
$-$4
B
4
C
$-$3
D
3
4
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{f}(x)=\frac{a \sin x+b \cos x}{c \sin x+d \cos x}$ is decreasing for all $x$ then

A
$\mathrm{ad}-\mathrm{bc}>0$
B
$ad - bc <0$
C
$a b-c d>0$
D
$\mathrm{ab }-\mathrm{cd}<0$
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