1
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{f}(x)=\sqrt{1+\cos ^2\left(x^2\right)}$, then $\mathrm{f}^{\prime}\left(\frac{\sqrt{\pi}}{2}\right)$ is

A

$\frac{\sqrt{\pi}}{6}$

B

$-\sqrt{\frac{\pi}{6}}$

C

$\frac{\pi}{\sqrt{6}}$

D

$\sqrt{\frac{\pi}{6}}$

2
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{f}(x)=\frac{\sin ^2 x}{1+\cot x}+\frac{\cos ^2 x}{1+\tan x}$, then the value of $\mathrm{f}^{\prime}\left(\frac{\pi}{6}\right)$ is equal to

A
0
B
$\frac{1}{2}$
C
$-\frac{1}{2}$
D
$\frac{\sqrt{3}}{2}$
3
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $y=\tan ^{-1}\left(\frac{12 x-64 x^3}{1-48 x^2}\right)$, then $\frac{\mathrm{d} y}{\mathrm{~d} x}=$

A
$\frac{3}{1+16 x^2}$
B
$\frac{4}{1+16 x^2}$
C
$\frac{12}{1+16 x^2}$
D
$\frac{1}{1+16 x^2}$
4
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If

$$ \sqrt{y-\sqrt{y-\sqrt{y-\ldots \ldots \ldots \infty}}}=\sqrt{x+\sqrt{x+\sqrt{x+\ldots \ldots \ldots \infty}}} $$

then $\frac{\mathrm{d} y}{\mathrm{~d} x}=$

A
$\frac{y+x+1}{y-x+1}$
B
$\frac{y-x-1}{y-x+1}$
C
$\frac{y-x+1}{y-x-1}$
D
1
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