If $$\lambda$$Cu is the wavelength of K$$\alpha$$ X-ray line of copper (atomic number 29) and $$\lambda$$Mo is the wavelength of the K$$\alpha$$ X-ray line of molybdenum (atomic number 42), then the ratio $$\lambda$$Cu/$$\lambda$$Mo is close to
The mass of a nucleus $$_Z^AX$$ is less than the sum of the masses of (A-Z) number of neutrons and Z number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of masses m1 and m2 only if (m1 + m2) < M. Also two light nuclei of masses m3 and m4 can undergo complete fusion and form a heavy nucleus of mass M' only if (m3 + m4) > M'. The masses of some neutral atoms are given in the table below :
| $$_1^1H$$ | 1.007825 u | $$_1^2H$$ | 2.014102 u |
|---|---|---|---|
| $$_3^6Li$$ | 6.015123 u | $$_3^7Li$$ | 7.016004 u |
| $$_{64}^{152}Gd$$ | 151.919803 u | $$_{82}^{206}Pb$$ | 205.974455 u |
| $$_1^3H$$ | 3.016050 u | $$_2^4He$$ | 4.002603 u |
| $$_{30}^{70}Zn$$ | 69.925325 u | $$_{34}^{82}Se$$ | 81.916709 u |
| $$_{83}^{209}Bi$$ | 208.980388 u | $$_{84}^{210}Po$$ | 209.982876 u |
(1 u = 932 MeV/c2)
The correct statement is
The mass of a nucleus $$_Z^AX$$ is less than the sum of the masses of (A-Z) number of neutrons and Z number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of masses m1 and m2 only if (m1 + m2) < M. Also two light nuclei of masses m3 and m4 can undergo complete fusion and form a heavy nucleus of mass M' only if (m3 + m4) > M'. The masses of some neutral atoms are given in the table below :
| $$_1^1H$$ | 1.007825 u | $$_1^2H$$ | 2.014102 u |
|---|---|---|---|
| $$_3^6Li$$ | 6.015123 u | $$_3^7Li$$ | 7.016004 u |
| $$_{64}^{152}Gd$$ | 151.919803 u | $$_{82}^{206}Pb$$ | 205.974455 u |
| $$_1^3H$$ | 3.016050 u | $$_2^4He$$ | 4.002603 u |
| $$_{30}^{70}Zn$$ | 69.925325 u | $$_{34}^{82}Se$$ | 81.916709 u |
| $$_{83}^{209}Bi$$ | 208.980388 u | $$_{84}^{210}Po$$ | 209.982876 u |
(1 u = 932 MeV/c2)
The kinetic energy (in keV) of the alpha particle, when the nucleus $$_{84}^{210}Po$$ at rest undergoes alpha decay, is
Match List I of the nuclear processes with List II containing parent nucleus and one of the end products of each process and then select the correct answer using the codes given below the lists :
| List I | List II | ||
|---|---|---|---|
| P. | Alpha decay | 1. | $$_8^{15}O \to _7^{15}N + ...$$ |
| Q. | $${\beta ^ + }$$ decay | 2. | $$_{91}^{238}U \to _{90}^{234}Th + ...$$ |
| R. | Fission | 3. | $$_{83}^{185}Bi \to _{82}^{184}Pb + ...$$ |
| S. | Proton emission | 4. | $$_{94}^{239}Pu \to _{57}^{140}La + ...$$ |