IIT-JEE 2009 Paper 2 Offline | Chemical Kinetics and Nuclear Chemistry Question 30 | Chemistry

IIT-JEE 2009 Paper 2 Offline

MCQ (Single Correct Answer)

-1

For a first-order reaction A $$\to$$ P, the temperature (T) dependent rate constant (k) was found to follow the equation $$\log k = - (2000){1 \over T} + 6.0$$. The pre-exponential factor A and activation energy $$E_a$$, respectively, are

$$1.0\times10^6~\mathrm{s^{-1}}$$ and 9.2 kJ mol$$^{-1}$$

$$6.0~\mathrm{s^{-1}}$$ and 16.6 kJ mol$$^{-1}$$

$$1.0\times10^6~\mathrm{s^{-1}}$$ and 16.6 kJ mol$$^{-1}$$

$$1.0\times10^6~\mathrm{s^{-1}}$$ and 38.3 kJ mol$$^{-1}$$

IIT-JEE 2008 Paper 1 Offline

MCQ (Single Correct Answer)

-1

Under the same reaction conditions, initial concentration of 1.386 mol dm$$^{-3}$$ of a substance becomes half in 40 seconds and 20 seconds through first order and zero order kinetics, respectively. Ratio $$\left( {{{{k_1}} \over {{k_0}}}} \right)$$ of the rate constants for first order ($$k_1$$) and zero order ($$k_0$$) of the reactions is:

0.5 mol$$^{-1}$$ dm$$^3$$

1.0 mol dm$$^{-3}$$

1.5 mol dm$$^{-3}$$

2.0 mol$$^{-1}$$ dm$$^3$$

IIT-JEE 2007 Paper 2 Offline

MCQ (Single Correct Answer)

-1

Consider a reaction aG + bH $$\to$$ Products. When concentration of both the reactants G and H is doubled, the rate increases by eight times. However, when concentration of G is doubled keeping the concentration of H fixed, the rate is doubled. The overall order of the reaction is

JEE Advanced Subjects