1
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

A closed vessel contains $10 \mathrm{~g}$ of an ideal gas $\mathbf{X}$ at $300 \mathrm{~K}$, which exerts $2 \mathrm{~atm}$ pressure. At the same temperature, $80 \mathrm{~g}$ of another ideal gas $\mathbf{Y}$ is added to it and the pressure becomes $6 \mathrm{~atm}$. The ratio of root mean square velocities of $\mathbf{X}$ and $\mathbf{Y}$ at $300 \mathrm{~K}$ is

A
$2 \sqrt{2}: \sqrt{3}$
B
$2 \sqrt{2}: 1$
C
$1: 2$
D
$2: 1$
2
JEE Advanced 2020 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
If the distribution of molecular speeds of a gas is as per the figure shown below, then the ratio of the most probable, the average, and the root mean square speeds, respectively, is

JEE Advanced 2020 Paper 1 Offline Chemistry - Gaseous State Question 9 English
A
1 : 1 : 1
B
1 : 1 : 1.224
C
1 : 1.128 : 1.224
D
1 : 1.128 : 1
3
IIT-JEE 2012 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

For one mole of a van der Waals gas when b = 0 and T = 300 K, the PV vs. 1/V plot is shown below. The value of the van der Waals constant a (atm L2 mol$$-$$2) is

IIT-JEE 2012 Paper 1 Offline Chemistry - Gaseous State Question 6 English

A
1.0
B
4.5
C
1.5
D
3.0
4
IIT-JEE 2009 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

The term that corrects for the attractive forces present in a real gas in the van der Waals equation is

A
$$nb$$
B
$${{a{n^2}} \over {{V^2}}}$$
C
$$ - {{a{n^2}} \over {{V^2}}}$$
D
$$ - nb$$
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