JEE Advanced 2020 Paper 1 Offline | Gaseous State Question 3 | Chemistry

JEE Advanced 2020 Paper 1 Offline

MCQ (Single Correct Answer)

-1

If the distribution of molecular speeds of a gas is as per the figure shown below, then the ratio of the most probable, the average, and the root mean square speeds, respectively, is

JEE Advanced 2020 Paper 1 Offline Chemistry - Gaseous State Question 9 English

JEE Advanced 2020 Paper 1 Offline Chemistry - Gaseous State Question 9 English

1 : 1 : 1

1 : 1 : 1.224

1 : 1.128 : 1.224

1 : 1.128 : 1

IIT-JEE 2012 Paper 1 Offline

MCQ (Single Correct Answer)

-1

For one mole of a van der Waals gas when b = 0 and T = 300 K, the PV vs. 1/V plot is shown below. The value of the van der Waals constant a (atm L² mol^$$-$$2) is

IIT-JEE 2012 Paper 1 Offline Chemistry - Gaseous State Question 6 English

1.0

4.5

1.5

3.0

IIT-JEE 2009 Paper 1 Offline

MCQ (Single Correct Answer)

-1

The term that corrects for the attractive forces present in a real gas in the van der Waals equation is

$$nb$$

$${{a{n^2}} \over {{V^2}}}$$

$$ - {{a{n^2}} \over {{V^2}}}$$

$$ - nb$$

IIT-JEE 1986

MCQ (Single Correct Answer)

-0.25

The average velocity of an ideal gas molecule at 27^oC is 0.3m/sec. The average velocity at 927^oC will be

0.6 m/sec

0.3 m/sec

0.9 m/sec

3.0 m/sec

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