MHT CET 2020 16th October Morning Shift | Gravitation Question 90 | Physics

A body is thrown from the surface of the earth velocity $$\mathrm{v} / \mathrm{s}$$. The maximum height above the earth's surface upto which it will reach is ($$R=$$ radius of earth, $$g=$$ acceleration due to gravity)

$$\frac{v R}{2 g R-v}$$

$$\frac{2 g A}{v^2(R-1)}$$

$$\frac{v R^2}{g R-v}$$

$$\frac{v^2 R}{2 g R-v^2}$$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

Consider a particle of mass $m$ suspended by a string at the equator. Let $R$ and $M$ denote radius and mass of the earth. If $\omega$ is the angular velocity of rotation of the earth about its own axis, then the tension on the string will be $\left(\cos 0^{\circ}=1\right)$

$\frac{G M m}{R^2}$

$\frac{G M m}{2 R^2}$

$\frac{G M m}{2 R^2}+m \omega^2 R$

$\frac{G M m}{R^2}-m \omega^2 R$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

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A hole is drilled half way to the centre of the earth. A body weighs 300 N on the surface of the earth. How much will, it weigh at the bottom of the hole?

200 N

250 N

120 N

150 N

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

What is the minimum energy required to launch a satellite of mass ' $m$ ' from the surface of the earth of mass ' $M$ ' and radius ' $R$ ' at an altitude $2 R$ ?

$\frac{G M m}{2 R}$

$\frac{2 G M m}{3 R}$

$\frac{G M m}{3 R}$

$\frac{5 G M m}{6 R}$

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