1
IIT-JEE 1980
Subjective
+4
-0
(i). A sample of MnSO4.4H2O is strongly heated in air. The residue is Mn3O4.
(ii). The residue is dissolved in 100 ml of 0.1N FeSO4 containing dilute H2SO4.
(iii). The solution reacts completely with 50 ml of KMnO4 solution.
(iv). 25 ml of the KMnO4 solution used in step (iii) requires 30 ml of 0.1 N FeSO4 solution for complete reaction.
Find the amount of MnSO4.4H2O present in the sample.
(ii). The residue is dissolved in 100 ml of 0.1N FeSO4 containing dilute H2SO4.
(iii). The solution reacts completely with 50 ml of KMnO4 solution.
(iv). 25 ml of the KMnO4 solution used in step (iii) requires 30 ml of 0.1 N FeSO4 solution for complete reaction.
Find the amount of MnSO4.4H2O present in the sample.
2
IIT-JEE 1980
Subjective
+4
-0
(a) One litre of a sample of hard water contains 1 mg of CaCl2 and 1 mg of MgCl2. Find the total hardness in terms of parts of CaCO3 per 106 parts of water by weight.
(b) A sample of hard water contains 20 mg of Ca++ ions per litre. How many milli-equivalent of Na2CO3 would be required to soften 1 litre of the sample?
(c) 1 gm of Mg is burnt in a closed vessel which contains 0.5gm of O2.
(i) Which reactant is left in excess?
(ii) Find the weight of the excess reactants.
(iii) How many milliliters of 0.5N H2SO4 will dissolve the residue in the vessel?
(b) A sample of hard water contains 20 mg of Ca++ ions per litre. How many milli-equivalent of Na2CO3 would be required to soften 1 litre of the sample?
(c) 1 gm of Mg is burnt in a closed vessel which contains 0.5gm of O2.
(i) Which reactant is left in excess?
(ii) Find the weight of the excess reactants.
(iii) How many milliliters of 0.5N H2SO4 will dissolve the residue in the vessel?
3
IIT-JEE 1979
Subjective
+4
-0
In the analysis of 0.5 g sample feldspar, a mixture of chlorides of sodium and potassium is obtained which weighs 0.1180g. Subsequent treatment of mixed chlorides with silver nitrate gives 0.2451 g of silver chloride. What is the percentage of sodium oxide and potassium oxide in feldspar.
4
IIT-JEE 1979
Subjective
+4
-0
5 ml of a gas containing only carbon and hydrogen were mixed with an excess of oxygen (30 ml) and the mixture exploded by means of an electric spark. After the explosion, the volume of the mixed gases remaining was 25 ml. On adding a concentrated solution of potassium hydroxide, the volume further diminished to 15 ml of the residual gas being pure oxygen. All volumes have been reduced to N.T.P. Calculate the molecular formula of the hydrocarbon gas.
Questions Asked from Some Basic Concepts of Chemistry (Subjective)
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