1
JEE Advanced 2022 Paper 2 Online
Numerical
+3
-1
Consider the strong electrolytes $Z_{m} X_{n}, U_{m} Y_{p}$ and $V_{m} X_{n}$. Limiting molar conductivity ( $\Lambda^{0}$ ) of $\mathrm{U}_{\mathrm{m}} \mathrm{Y}_{\mathrm{p}}$ and $\mathrm{V}_{\mathrm{m}} \mathrm{X}_{\mathrm{n}}$ are 250 and $440 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$, respectively. The value of $(\mathrm{m}+\mathrm{n}+\mathrm{p})$ is
Given:
$\lambda^{0}$ is the limiting molar conductivity of ions
The plot of molar conductivity ( $\Lambda$ ) of $\mathrm{Z}_{\mathrm{m}} \mathrm{X}_{\mathrm{n}} v s\, \mathrm{c}^{1 / 2}$ is given below.

Given:
Ion | $\mathrm{Z}^{\mathrm{n}+}$ | $\mathrm{U}^{\mathrm{p}+}$ | $\mathrm{V}^{\mathrm{n}+}$ | $\mathrm{X}^{\mathrm{m}-}$ | $\mathrm{Y}^{\mathrm{m}-}$ |
---|---|---|---|---|---|
$\lambda^{0}\left(\mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\right)$ | $50.0$ | $25.0$ | $100.0$ | $80.0$ | $100.0$ |
$\lambda^{0}$ is the limiting molar conductivity of ions
The plot of molar conductivity ( $\Lambda$ ) of $\mathrm{Z}_{\mathrm{m}} \mathrm{X}_{\mathrm{n}} v s\, \mathrm{c}^{1 / 2}$ is given below.

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2
JEE Advanced 2022 Paper 1 Online
Numerical
+3
-0
The reduction potential $\left(E^{0}\right.$, in $\left.\mathrm{V}\right)$ of $\mathrm{MnO}_{4}^{-}(\mathrm{aq}) / \mathrm{Mn}(\mathrm{s})$ is __________.
[Given: $E_{\left(\mathrm{MnO}_{4}^{-}(\mathrm{aq}) / \mathrm{MnO}_{2}(\mathrm{~s})\right)}^{0}=1.68 \mathrm{~V} ; E_{\left(\mathrm{MnO}_{2}(\mathrm{~s}) / \mathrm{Mn}^{2+}(\mathrm{aq})\right)}^{0}=1.21 \mathrm{~V} ; E_{\left(\mathrm{Mn}^{2+}(\mathrm{aq}) / \mathrm{Mn}(\mathrm{s})\right)}^{0}=-1.03 \mathrm{~V}$ ]
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3
JEE Advanced 2021 Paper 2 Online
Numerical
+2
-0
At 298 K, the limiting molar conductivity of a weak monobasic acid is 4 $$\times$$ 102 S cm2 mol$$-$$1. At 298 K, for an aqueous solution of the acid the degree of dissociation is $$\alpha$$ and the molar conductivity is y $$\times$$ 102 S cm2 mol$$-$$1. At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes 3y $$\times$$ 102 S cm2 mol$$-$$1.
The value of $$\alpha$$ is __________.
The value of $$\alpha$$ is __________.
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4
JEE Advanced 2021 Paper 2 Online
Numerical
+2
-0
At 298 K, the limiting molar conductivity of a weak monobasic acid is 4 $$\times$$ 102 S cm2 mol$$-$$1. At 298 K, for an aqueous solution of the acid the degree of dissociation is $$\alpha$$ and the molar conductivity is y $$\times$$ 102 S cm2 mol$$-$$1. At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes 3y $$\times$$ 102 S cm2 mol$$-$$1.
The value of y is __________.
The value of y is __________.
Your input ____
Questions Asked from Electrochemistry (Numerical)
Number in Brackets after Paper Indicates No. of Questions
JEE Advanced 2022 Paper 2 Online (1)
JEE Advanced 2022 Paper 1 Online (1)
JEE Advanced 2021 Paper 2 Online (2)
JEE Advanced 2020 Paper 1 Offline (1)
JEE Advanced 2018 Paper 2 Offline (1)
JEE Advanced 2018 Paper 1 Offline (1)
JEE Advanced 2017 Paper 1 Offline (1)
JEE Advanced 2015 Paper 2 Offline (1)
JEE Advanced 2015 Paper 1 Offline (1)
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