1
JEE Advanced 2020 Paper 2 Offline
Numerical
+3
-1
Consider the following compounds in the liquid form :
O2, HF, H2O, NH3, H2O2, CCl4, CHCl3, C6H6, C6H5Cl
When a charged comb is brought near their flowing stream, how many of them show deflection as per the following figure?
O2, HF, H2O, NH3, H2O2, CCl4, CHCl3, C6H6, C6H5Cl
When a charged comb is brought near their flowing stream, how many of them show deflection as per the following figure?
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2
JEE Advanced 2017 Paper 1 Offline
Numerical
+3
-0
Among $${H_2},H{e_2}^ + ,L{i_2},$$ $$B{e_2},{B_2},{C_2},{N_2},O_2^ - $$ and $${F_2},$$ the number of diamagnetic species is
(Atomic numbers : $$H = 1,He = 2,$$ $$Li = 3,Be = 4,$$ $$B = 5,C = 6,$$ $$N = 7,$$ $$O = 8,F = 9$$)
(Atomic numbers : $$H = 1,He = 2,$$ $$Li = 3,Be = 4,$$ $$B = 5,C = 6,$$ $$N = 7,$$ $$O = 8,F = 9$$)
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3
JEE Advanced 2015 Paper 1 Offline
Numerical
+4
-0
Among the triatomic molecules/ions, BeCl2, $$N_3^-$$, N2O, $$NO_2^+$$, O3, SCl2, $$ICl_2^-$$, $$I_3^-$$ and XeF2, the total number of linear molecule(s)/ion(s) where the hybridization of the central atom does not have contribution from the d-orbital(s) is
[Atomic number: S = 16, Cl = 17, I = 53 and Xe = 54]
[Atomic number: S = 16, Cl = 17, I = 53 and Xe = 54]
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4
JEE Advanced 2014 Paper 1 Offline
Numerical
+3
-0
A list of species having the formula XZ4 is given below.
XeF4, SF4 ,SiF4, $$BF_4^-$$, $$BrF_4^-$$, [Cu(NH3)4]2+, [FeCl4]2-, [CoCl4]2- and [PtCl4]2-
Defining shape on the basis of the location of X and Z atoms, the total number of species having a square planar shape is
XeF4, SF4 ,SiF4, $$BF_4^-$$, $$BrF_4^-$$, [Cu(NH3)4]2+, [FeCl4]2-, [CoCl4]2- and [PtCl4]2-
Defining shape on the basis of the location of X and Z atoms, the total number of species having a square planar shape is
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Questions Asked from Chemical Bonding & Molecular Structure (Numerical)
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