Among $${H_2},H{e_2}^ + ,L{i_2},$$ $$B{e_2},{B_2},{C_2},{N_2},O_2^ - $$ and $${F_2},$$ the number of diamagnetic species is

(Atomic numbers : $$H = 1,He = 2,$$ $$Li = 3,Be = 4,$$ $$B = 5,C = 6,$$ $$N = 7,$$ $$O = 8,F = 9$$)

Among the triatomic molecules/ions, BeCl₂, $$N_3^-$$, N₂O, $$NO_2^+$$, O₃, SCl₂, $$ICl_2^-$$, $$I_3^-$$ and XeF₂, the total number of linear molecule(s)/ion(s) where the hybridization of the central atom does not have contribution from the d-orbital(s) is

[Atomic number: S = 16, Cl = 17, I = 53 and Xe = 54]

A list of species having the formula XZ₄ is given below.

XeF₄, SF₄ ,SiF₄, $$BF_4^-$$, $$BrF_4^-$$, [Cu(NH₃)₄]²⁺, [FeCl₄]^2-, [CoCl₄]^2- and [PtCl₄]^2-

Defining shape on the basis of the location of X and Z atoms, the total number of species having a square planar shape is

Based on VSEPR theory, the number of 90 degree F-Br-F angles in BrF₅ is