JEE Advanced 2014 Paper 2 Offline | Work Power & Energy Question 9 | Physics

1

JEE Advanced 2014 Paper 2 Offline

MCQ (Single Correct Answer)

+3

-1

A tennis ball is dropped on a horizontal smooth surface. It bounces back to its original position after hitting the surface. The force on the ball during the collision is proportional to the length of compression of the ball. Which one of the following sketches describes the variation of its kinetic energy K with time t most appropriately? The figures are only illustrative and not to the scale.

A

JEE Advanced 2014 Paper 2 Offline Physics - Work Power & Energy Question 26 English Option 1

B

JEE Advanced 2014 Paper 2 Offline Physics - Work Power & Energy Question 26 English Option 2

C

JEE Advanced 2014 Paper 2 Offline Physics - Work Power & Energy Question 26 English Option 3

D

JEE Advanced 2014 Paper 2 Offline Physics - Work Power & Energy Question 26 English Option 4

2

JEE Advanced 2013 Paper 2 Offline

MCQ (Single Correct Answer)

+3

-0.75

A small block of mass 1 kg is released from rest at the top of a rough track. The track is circular arc of radius 40 m. The block slides along the track without toppling and a frictional force acts on it in the direction opposite to the instantaneous velocity. The work done in overcoming the friction up to the point Q, as shown in the figure, below, is 150 J. (Take the acceleration due to gravity, g = 10 m/s²)

JEE Advanced 2013 Paper 2 Offline Physics - Work Power & Energy Question 20 English Comprehension

The speed of the block when it reaches the point Q is

A

5 ms^-1

B

10 ms^-1

C

$$10\sqrt 3 $$ ms^-1

D

20 ms^-1

3

JEE Advanced 2013 Paper 2 Offline

MCQ (Single Correct Answer)

+3

-0.75

A small block of mass 1 kg is released from rest at the top of a rough track. The track is circular arc of radius 40 m. The block slides along the track without toppling and a frictional force acts on it in the direction opposite to the instantaneous velocity. The work done in overcoming the friction up to the point Q, as shown in the figure, below, is 150 J. (Take the acceleration due to gravity, g = 10 m/s²)

JEE Advanced 2013 Paper 2 Offline Physics - Work Power & Energy Question 19 English Comprehension

The magnitude of the normal reaction that acts on the block at the point Q is

A

7.5 N

B

8.6 N

C

11.5 N

D

22.5 N

4

JEE Advanced 2013 Paper 1 Offline

MCQ (Single Correct Answer)

+2

-0.5

The work done on a particle of mass m by a force $$$K\left[ {{x \over {{{\left( {{x^2} + {y^2}} \right)}^{3/2}}}}\widehat i + {y \over {{{\left( {{x^2} + {y^2}} \right)}^{3/2}}}}\widehat j} \right]$$$ (K being a constant of appropriate dimensions), when the particle is taken from the point $$\left( {a,0} \right)$$ to the point $$\left( {0,a} \right)$$ along a circular path of radius a about the origin in the x-y plane is

A

$${{2K\pi } \over a}$$

B

$${{K\pi } \over a}$$

C

$${{K\pi } \over {2a}}$$

D

0