1
JEE Advanced 2019 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1 A free hydrogen atom after absorbing a photon of wavelength $$\lambda$$a gets excited from the state n = 1 to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon of wavelength $$\lambda$$e. Let the change in momentum of atom due to the absorption and the emission be $$\Delta {p_a}$$ and $$\Delta {p_e}$$, respectively. If $${{{\lambda _a}} \over {{\lambda _e}}} = {1 \over 5}$$, which of the option(s) is/are correct? [Use hc = 1242 eVnm; 1 nm = 10-9 m, h and c are Planck's constant and speed of light in vacuum, respectively]
A
The ratio of kinetic energy of the electron in the state n = m to the state, n = 1 is $${1 \over 4}$$
B
m = 2
C
$${{\Delta {p_a}} \over {\Delta {p_e}}} = {1 \over 2}$$
D
$$\lambda$$e = 418 nm
2
JEE Advanced 2018 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1
In a radioactive decay chain, $${}_{90}^{232}Th$$ nucleus decays to $${}_{82}^{212}Pb$$ nucleus. Let $${N_\alpha }$$ and $${N_\beta }$$ be the number of $$\alpha$$ and $${\beta ^ - }$$ particles, respectively, emitted in this decay process. Which of the following statements is (are) true?
A
$${N_\alpha } = 5$$
B
$${N_\alpha } = 6$$
C
$${N_\beta } = 2$$
D
$${N_\beta } = 4$$
3
JEE Advanced 2016 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
Highly excited states for hydrogen-like atoms (also called Rydberg states) with nuclear charge Ze are defined by their principle quantum number n, where n >> 1. Which of the following statement(s) is(are) true?
A
Relative change in the radii of two consecutive orbitals does not depend on Z.
B
Relative change in the radii of two consecutive orbitals varies as 1/n
C
Relative change in the energy of two consecutive orbitals varies as 1/n3
D
Relative change in the angular momenta of two consecutive orbitals varies as 1/n
4
JEE Advanced 2015 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2
A fission reaction is given by $$_{92}^{236}U \to _{54}^{140}Xe + _{38}^{94}Sr + x + y$$, where x and y are two particles. Considering $$_{92}^{236}U$$ to be at rest, the kinetic energies of the products are denoted by $${K_{Xe}},{K_{Sr}},{K_x}(2MeV)$$ $$\text { and } \mathrm{K}_{\mathrm{y}}(2 \mathrm{MeV})$$, respectively. Let the binding energies per nucleon of $$_{92}^{236}U$$, $$_{54}^{140}Xe$$ and $$_{38}^{94}Sr$$ be 7.5 MeV, 8.5 MeV and 8.5 MeV, respectively. Considering different conservation laws, the correct options is/are
A
x = n, y = n, Ksr = 129 MeV, KXe = 86 MeV
B
x = p, y = e$$-$$, Ksr = 129 MeV, KXe = 86 MeV
C
x = p, y = n, Ksr = 129 MeV, KXe = 86 MeV
D
x = n, y = n, Ksr = 86 MeV, KXe = 129 MeV
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