1
JEE Advanced 2019 Paper 2 Offline
Numerical
+3
-0
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A 10 cm long perfectly conducting wire PQ is moving with a velocity I cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1$$\Omega $$ as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x $$ \times $$ 10-3 A, where the value of x is ...........

[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed. Given e-1 = 0.37, where e is base of the natural logarithm]

JEE Advanced 2019 Paper 2 Offline Physics - Electromagnetic Induction Question 14 English
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2
JEE Advanced 2016 Paper 1 Offline
Numerical
+3
-0
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Two inductors L1 (inductance 1mH, internal resistance 3$$\Omega$$) and L2 (inductance 2 mH, internal resistance 4$$\Omega$$), and a resistor R (resistance 12$$\Omega$$) are all connected in parallel across a 5V battery. The circuit is switched on at time t = 0. The ratio of the maximum to the minimum current (Imax / Imin) drawn from the battery is
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3
IIT-JEE 2012 Paper 1 Offline
Numerical
+4
-0

A circular wire loop of radius R is placed in the xy plane centred at the origin O. A square loop of side a(a << R) having two turns is placed with its centre at z = $$\sqrt3$$R along the axis of the circular wire loop, as shown in the figure. The plane of the square loop makes an angle of 45$$^\circ$$ with respect to z-axis. If the mutual inductance between the loops is given by $${{{\mu _0}{a^2}} \over {{2^{p/2}}R}}$$, then the value of p is ___________.

IIT-JEE 2012 Paper 1 Offline Physics - Electromagnetic Induction Question 6 English

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4
IIT-JEE 2010 Paper 2 Offline
Numerical
+3
-0

At time t = 0, a battery of 10 V is connected across points A and B in the given circuit. If the capacitors have no charge initially, at what time (in seconds) does the voltage across them becomes 4 V? (Take ln5 = 1.6, ln3 = 1.1)

IIT-JEE 2010 Paper 2 Offline Physics - Electromagnetic Induction Question 5 English

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