$${I_C}\, = \,1.3\,mA,\,{R_C}\, = \,2\,k\Omega ,\,{R_E}\, = \,500\,\Omega ,$$

$${V_T}\, = \,26\,mV,\,\beta \, = \,100,\,{V_{CC}}\, = \,15V,$$

$${V_s}\, = \,0.01\,\sin \left( {\omega t} \right)\,V\,and\,{C_b}\, = \,{C_C}\, = \,10\,\mu F.$$

(a)What is the small-signal voltage gain, $${A_V} = {V_0}/{V_s}?$$

(b)What is the approximate $${A_{v,}}\,\,if\,\,{C_e}\,\,$$ is removed?

(c)What will $${V_0}\,be\,if\,{C_b}$$ is short circuited?

_{bias}is ideal, and the transistor has very large$$\beta ,\,\,{r_{b\,\,}} = \,\,0,$$ and the $${r_0}\, \to \,\infty $$.

Determine the ac small-signal mid-band and voltage gain $$\left( {{V_o}/{V_s}} \right),$$ input resistance (R_{1}, and output resistance (R_{0}) of the circuit. Assume $${V_{T\,\,}} = \,\,26\,mV.$$

_{o}seen by the output terminals, ignore the effects of R

_{1}and R

_{2}.

_{C}= 1mA. Supply is V

_{CC}= 5V.

The N/W components have following values, R_{C} = 2$$k\Omega $$,

R_{S} = $$1.4k\Omega $$,

R_{E} = $$100\Omega $$.

The transistor has specifications, $$\beta \,\, = \,\,100$$

and base spreading resistance $${r_{bb\,}}^1\, = \,100\Omega $$

Evaluate input resistance R_{i} for two cases. At a frequency of 10 kHz

(a)C_{E}, the bypass capacitor across R_{E} is 25 $$\mu F$$

(b)The bypass capacitor C_{E} is removed leaving R_{E} unbypassed.