1
JEE Advanced 2020 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
As shown schematically in the figure, two vessels contain water solutions (at temperature T) of
potassium permanganate (KMnO4) of different concentrations n1 and n2 (n1 > n2) molecules per
unit volume with $$\Delta $$n = (n1 − n2) << n1. When they are connected by a tube of small length l and
cross-sectional area S, KMnO4 starts to diffuse from the left to the right vessel through the tube.
Consider the collection of molecules to behave as dilute ideal gases and the difference in their partial
pressure in the two vessels causing the diffusion. The speed v of the molecules is limited by the
viscous force −$$\beta $$v on each molecule, where $$\beta $$ is a constant. Neglecting all terms of the order ($$\Delta $$n)2,
which of the following is/are correct? (kB is the Boltzmann constant)
2
JEE Advanced 2020 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
A football of radius R is kept on a hole of radius r (r < R) made on a plank kept horizontally. One
end of the plank is now lifted so that it gets tilted making an angle $$\theta $$ from the horizontal as shown in
the figure below. The maximum value of $$\theta $$ so that the football does not start rolling down the plank
satisfies (figure is schematic and not drawn to scale)
3
JEE Advanced 2020 Paper 1 Offline
Numerical
+4
-0
A stationary tuning fork is in resonance with an air column in a pipe. If the tuning fork is moved with
a speed of 2 ms−1
in front of the open end of the pipe and parallel to it, the length of the pipe should
be changed for the resonance to occur with the moving tuning fork. If the speed of sound in air is
320 ms−1, the smallest value of the percentage change required in the length of the pipe is
____________.
Your input ____
4
JEE Advanced 2020 Paper 1 Offline
Numerical
+4
-0
A circular disc of radius R carries surface charge density
$$\sigma \left( r \right) = {\sigma _0}\left( {1 - {r \over R}} \right)$$, where $$\sigma $$0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is $$\phi $$0. Electric flux through another spherical surface of radius $${R \over 4}$$ and concentric with the disc is $$\phi $$. Then the ratio $${{{\phi _0}} \over \phi }$$ is ________.
$$\sigma \left( r \right) = {\sigma _0}\left( {1 - {r \over R}} \right)$$, where $$\sigma $$0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is $$\phi $$0. Electric flux through another spherical surface of radius $${R \over 4}$$ and concentric with the disc is $$\phi $$. Then the ratio $${{{\phi _0}} \over \phi }$$ is ________.
Your input ____
Paper analysis
Total Questions
Chemistry
18
Mathematics
18
Physics
18
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