1
JEE Advanced 2020 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
A small roller of diameter 20 cm has an axle of diameter 10 cm (see figure below on the left). It is
on a horizontal floor and a meter scale is positioned horizontally on its axle with one edge of the scale
on top of the axle (see figure on the right). The scale is now pushed slowly on the axle so that it
moves without slipping on the axle, and the roller starts rolling without slipping. After the roller has
moved 50 cm, the position of the scale will look like (figures are schematic and not drawn to scale)
2
JEE Advanced 2020 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
A football of radius R is kept on a hole of radius r (r < R) made on a plank kept horizontally. One
end of the plank is now lifted so that it gets tilted making an angle $$\theta $$ from the horizontal as shown in
the figure below. The maximum value of $$\theta $$ so that the football does not start rolling down the plank
satisfies (figure is schematic and not drawn to scale)
3
JEE Advanced 2020 Paper 1 Offline
Numerical
+4
-0
A stationary tuning fork is in resonance with an air column in a pipe. If the tuning fork is moved with
a speed of 2 ms−1
in front of the open end of the pipe and parallel to it, the length of the pipe should
be changed for the resonance to occur with the moving tuning fork. If the speed of sound in air is
320 ms−1, the smallest value of the percentage change required in the length of the pipe is
____________.
Your input ____
4
JEE Advanced 2020 Paper 1 Offline
Numerical
+4
-0
A circular disc of radius R carries surface charge density
$$\sigma \left( r \right) = {\sigma _0}\left( {1 - {r \over R}} \right)$$, where $$\sigma $$0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is $$\phi $$0. Electric flux through another spherical surface of radius $${R \over 4}$$ and concentric with the disc is $$\phi $$. Then the ratio $${{{\phi _0}} \over \phi }$$ is ________.
$$\sigma \left( r \right) = {\sigma _0}\left( {1 - {r \over R}} \right)$$, where $$\sigma $$0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is $$\phi $$0. Electric flux through another spherical surface of radius $${R \over 4}$$ and concentric with the disc is $$\phi $$. Then the ratio $${{{\phi _0}} \over \phi }$$ is ________.
Your input ____
Paper analysis
Total Questions
Chemistry
18
Mathematics
18
Physics
18
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