1
JEE Advanced 2018 Paper 2 Offline
Numerical
+3
-0
To measure the quantity of $$MnC{l_2}$$ dissolved in an aqueous solution, it was completely converted to $$KMn{O_4}$$ using the reaction,
$$MnC{l_2} + {K_2}{S_2}{O_8} + {H_2}O \to KMn{O_4} + {H_2}S{O_4} + HCl$$ (equation not balanced).
Few drops of concentrated $$HCl$$ were added to this solution and gently warmed. Further, oxalic acid ($$225$$ $$mg$$) was added in portions till the colour of the permanganate ion disappeared. The quantity of $$MnC{l_2}$$ (in mg) present in the initial solution is ____________.
(Atomic weights in $$g\,\,mo{l^{ - 1}}:Mn = 55,Cl = 35.5$$ )
$$MnC{l_2} + {K_2}{S_2}{O_8} + {H_2}O \to KMn{O_4} + {H_2}S{O_4} + HCl$$ (equation not balanced).
Few drops of concentrated $$HCl$$ were added to this solution and gently warmed. Further, oxalic acid ($$225$$ $$mg$$) was added in portions till the colour of the permanganate ion disappeared. The quantity of $$MnC{l_2}$$ (in mg) present in the initial solution is ____________.
(Atomic weights in $$g\,\,mo{l^{ - 1}}:Mn = 55,Cl = 35.5$$ )
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2
JEE Advanced 2014 Paper 1 Offline
Numerical
+4
-0
If the value of Avogadro number is 6.023 $$\times$$ 1023 mol-1 and the value of Boltzmann constant is 1.380 $$\times$$ 10-23 J K-1, then the number of significant digits in the calculated value of the universal gas constant is
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3
IIT-JEE 2012 Paper 1 Offline
Numerical
+3
-0
29.2 % (w/w) HCl stock solution has density of 1.25 g mL -1 . The molecular weight of HCl is 36.5 g mol -1 .
The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is
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4
IIT-JEE 2010 Paper 1 Offline
Numerical
+2
-0
A student performs a titration with different burettes and finds titre values of 25.2 mL, 25.25 mL, and 25.0 mL. The number of significant figures in the average titre value is
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Questions Asked from Some Basic Concepts of Chemistry (Numerical)
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