1
JEE Advanced 2015 Paper 2 Offline
Numerical
+4
-0
The energy of a system as a function of time t is given as E(t) = $${A^2}\exp \left( { - \alpha t} \right)$$, where $$\alpha = 0.2\,{s^{ - 1}}$$. The measurement of A has an error of 1.25 %. If the error in the measurement of time is 1.50 %, the percentage error in the value of E(t) at t = 5 s is
2
JEE Advanced 2014 Paper 1 Offline
Numerical
+3
-0
During Searle's experiment, zero of the Vernier scale lies between 3.20 $$\times$$ 10-2 m and 3.25 $$\times$$ 10-2 m of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between 3.20 $$\times$$ 10-2 m and 3.25 $$\times$$ 10-2 m of the main scale but now the 45th division of Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is 8 $$\times$$ 10-7 m2. The least count of the Vernier scale is 1.0 $$\times$$ 10-5 m. The maximum percentage error in the Young's modulus of the wire is
3
JEE Advanced 2014 Paper 1 Offline
Numerical
+3
-0
To find the distance d over which a signal can be seen clearly in foggy conditions, a railways engineer uses dimensional analysis and assumes that the distance depends on the mass density $$\rho$$ of the fog, intensity (power/area) S of the light from the signal and its frequency f. The engineer finds that d is proportional to S1/n. The value of n is