1

### JEE Advanced 2015 Paper 2 Offline

Numerical
The energy of a system as a function of time t is given as E(t) = ${A^2}\exp \left( { - \alpha t} \right)$, where $\alpha = 0.2\,{s^{ - 1}}$. The measurement of A has an error of 1.25 %. If the error in the measurement of time is 1.50 %, the percentage error in the value of E(t) at t = 5 s is

2

### JEE Advanced 2014 Paper 1 Offline

Numerical
During Searle's experiment, zero of the Vernier scale lies between 3.20 $\times$ 10-2 m and 3.25 $\times$ 10-2 m of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between 3.20 $\times$ 10-2 m and 3.25 $\times$ 10-2 m of the main scale but now the 45th division of Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is 8 $\times$ 10-7 m2. The least count of the Vernier scale is 1.0 $\times$ 10-5 m. The maximum percentage error in the Young's modulus of the wire is

3

### JEE Advanced 2014 Paper 1 Offline

Numerical
To find the distance d over which a signal can be seen clearly in foggy conditions, a railways engineer uses dimensional analysis and assumes that the distance depends on the mass density $\rho$ of the fog, intensity (power/area) S of the light from the signal and its frequency f. The engineer finds that d is proportional to S1/n. The value of n is

#### Questions Asked from Units & Measurements

On those following papers in Numerical
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JEE Advanced 2019 Paper 2 Offline (1)
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JEE Advanced 2015 Paper 2 Offline (1)
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JEE Advanced 2014 Paper 1 Offline (2)
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